For a regular cube:
side length =
![s[tex] volume = [tex]s^3](https://tex.z-dn.net/?f=s%5Btex%5D%20volume%20%3D%20%5Btex%5Ds%5E3)
This problem has a lot of distributing. I suggest you use a grid to make sure each term is distributed (see attached image on how to do this)
For our problem:
side length =


(use FOIL)

Multiplying 5a(25a²+40ab+16b²) =

Multiplying 4b(25a²+40ab+16b²) =

Combine like terms. (200a²b + 100a²b = 300a²b, 80ab² + 160ab² = 240ab²)
volume = s³ =
Add he fractions first, 1/9 + 4/9 which is 5/9. Now add the whole numbers which are 2 and 7, and you get 9. Your fraction will be 9 5/9 and this number cannot be simplified anymore.
Answer:
Step-by-step explanation:
Couldn't see the first to well but the 2nd one is x=1.337
We need to assign a value for x to check the possible values of y.
1st inequality: y < -0.75x
X = - 1 ; y < -0.75(-1) ; y < 0.75 possible coordinate (-1,0.75) LOCATED AT THE 2ND QUADRANT
X = 0 ; y < -0.75(0) ; y < 0 possible coordinate (0,0) ORIGIN
X = 1 ; y < -0.75(1) ; y < -0.75 possible coordinate (1,-0.75) LOCATED AT THE 4TH QUADRANT
2nd inequality: y < 3x -2
X = -1 ; y < 3(-1) – 2 ; y < -5 possible coordinate (-1,-5) LOCATED AT THE 4TH QUADRANT
X = 0 ; y < 3(0) – 2 ; y < -2 possible coordinate (0,-2) LOCATED AT THE 4TH QUADRANT
X = 1 ; y < 3(1) – 2 ; y <<span> 1 possible coordinate (1,1) LOCATED AT THE 1ST QUADRANT
The actual solution to the system lies on the 4TH QUADRANT.
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