Answer:
(Compression)
Explanation:
The aluminium bar is experimenting a compression due to an axial force, that is, a force exerted on the bar in its axial direction. (See attachment for further details) Under the assumption of small strain, the deformation experimented by the bar is equal to:
Where:
- Load experimented by the bar, measured in newtons.
- Length of the bar, measured in meters.
- Cross section area of the bar, measured in square meters.
- Elasticity module, also known as Young's Module, measured in pascals, that is, newtons per square meter.
The cross section area of the bar is now computed: (, )
Where:
- Outer diameter, measured in meters.
- Inner diameter, measured in meters.
The total contraction of the bar due to compresive load is: (, , , ) (Note: The negative sign in the load input means the existence of compressive load)
(Compression)