22 m/s because you just have to take the old speed and add it to how much he or she sped up to get the answer bebe:)
Hello there!
The answer would be- False. Air masses do not mix at fronts.
Hope this helps... tell me if i am incorrect! Thanks!
~DL ☆♡☆♡
Given Information:
diameter = d = 15 mm
Length = L = 20 mm
Axial load = P = 300 N
Eₚ = 2.70x10⁹ Pa
vₚ = 0.4
Required Information:
Change in length = ?
Change in diameter = ?
Answer:
Change in length = 0.01257 mm
Change in diameter = -0.003772 mm
Explanation:
Stress is given by
σ = P/A
Where P is axial load and A is the area of the cross-section
A = 0.25πd²
A = 0.25π(0.015)²
A = 0.000176 m²
σ = 300/0.000176
σ = 1697792.8 Pa
The longitudinal stress is given by
εlong = σ/Eₚ
εlong = 1697792.8/2.70x10⁹
εlong = 0.0006288 mm/mm
The change in length can be found by using
δ = εlong*L
δ = 0.0006288*20
δ = 0.01257 mm
The lateral stress is given by
εlat = -vₚ*εlong
εlat = -0.4*0.0006288
εlat = -0.0002515 mm/mm
The change in diameter can be found by using
Δd = εlat*d
Δd = -0.0002515*15
Δd = -0.003772 mm
Therefore, the change in length is 0.01257 mm and the change in diameter is -0.003772 mm
After x seconds, an object will fall
where a is acceleration due to gravity and t is time
so when t=3.3
the distance it will fall is
=53.361m
it will fal 53.361 meters
Answer:
average speed = 1.73m/s
average velocity = 3.33m/s
Explanation:
<em>we'll</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>average</em><em> </em><em>speed</em><em> </em><em>first</em>
<em>average</em><em> </em><em>speed</em><em> </em><em>=</em><em> </em><em>total</em><em> </em><em>distance</em><em> </em><em>/</em><em> </em><em>total</em><em> </em><em>time</em><em> </em>
<em>his</em><em> </em><em>total</em><em> </em><em>distance</em><em> </em><em>is</em><em> </em>300m + 100m
= 400m
and total time should be taken in seconds as you know
((2×60)+50) + 60s
= 230s
so let's divide,
400m/230s
1.73 m/s
next, mean velocity
that is,
mean velocity = final- initial displacement/time
we have to note <em>displacement</em><em> </em>( this is the distance between the initial point to final point) here
the displacement is 300-100
so, 200m
we already calculated total time
but that cant be taken here
230 - 170
is the original time to travel 200m
that is, 60s
so we divide
200/60
3.33m/s