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sukhopar [10]
3 years ago
9

A baseball pitcher throws a ball at 97.0 mi/h in the horizontal direction. How far does the ball fall vertically by the time it

reaches home plate, which is a horizontal distance of 60.5 ft away? (Express your answer in units of feet. Neglect air resistance.)
Physics
1 answer:
mario62 [17]3 years ago
7 0

Answer:

Explanation:

1 mile=5280 ft

1 hour=3600 seconds

Changing speed from mi/h to ft/s

97 mi/h \times \frac {5280}{3600}=142.2666667 ft/s\approx 142.27 ft/s

Time of flight, t=\frac {distance}{speed}=\frac {60.5}{142.27}=0.425257732 s\approx 0.425 s

From fundamental kinematics equations

h=0.5gt^{2} where g is acceleration due to gravity whose value is taken as 32.2 ft/s2 and h is the distance

By substitution

h=0.5\times 32.2\times 0.425^{2}=2.9080625 m\approx 2.91 m

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0.01 C

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