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yaroslaw [1]
3 years ago
8

Passengers in a high-flying jumbo jet feel their normal weight in flight, while passengers in an orbiting space vehicle do not,

because passengers in the space vehicle are
A) Without support forces.
B) Beyond the main pull of Earth's gravity
C) above Earth's atmosphere
D) all of the above
E) None of the above.
Physics
1 answer:
daser333 [38]3 years ago
4 0

Answer:E none of the above

Explanation:

When a space shuttle orbiting around the earth then earth gravitational force keeps the shuttle in its orbit by providing centripetal force. Tangential velocity makes the shuttle to revolve around the earth. Earth gravitational pull is significant to make the shuttle move in orbit while the Passengers feel weightlessness because they are falling downward but never able to reach as they move fast enough such that earth curves away them.                        

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What is the electric field at a location b → = <-0.5, -0.4, 0> m, due to a particle with charge +2 nC located at the origi
Naddika [18.5K]

Answer:

E = \frac{8.99 x10^{9} \frac{Nm^2}{C^2} * 2x10^{-9} C}{(0.64m)^2} =43.85N

Explanation:

For this case we assume that we want to find the electrical field at the point P as we can see on the figure attached.

The electrical field wormula is given by:

E = \frac{K Q}{d^2}

Where r is the distance from the point and the charge. On this case we can use the Pythagoras theorem and we got:

d^2 = (-0.5m)^2 +(-0.4)^2 = 0.41m^2

d =\sqrt{0.41}= 0.64m

And now we can replace into the formula since we know that Q = 2nC= 2x10^{-9}C and K = 8.99 x10^{9} \frac{Nm^2}{C^2}, and we got:

E = \frac{8.99 x10^{9} \frac{Nm^2}{C^2} * 2x10^{-9} C}{(0.64m)^2} =43.85N

4 0
3 years ago
Can classical physics be used to accurately describe a satellite moving at a speed of 7500 m/s? explain why or why not.
gogolik [260]

The classical physics works on the Newton's laws of motion. It is applicable on heavenly bodies which are governed by the gravitational force. On the other hand, Quantum Physics is applicable for very low mass and sized bodies like electron, protons etc. The classical physics would accurately describe the motion of satellite moving with speed 7500 m/s using the following formula:

r=\frac {GM}{v^{2}}

where G is the gravitational constant, M is the mass of the planet and v is the orbital speed. Then radius of the orbit can be described by this formula.

3 0
4 years ago
To prevent burnout during your fitness plan, you need to start out with what plan?
Blababa [14]
A warm up plan . Hope that helps
8 0
4 years ago
A bicyclist rides 1.59 km due east, while the resistive force from the air has a magnitude of 7.00 N and points due west. The ri
kramer

Answer:

The required work done by the resistive force = -22.3 kJ

Explanation:

We understand that the amount of work done for a force F and displacements is provided as the product of force multiplied by displacement, which can be represented as W = F.S

Now, when the cyclist travels east and returns west, the force and displacement directions will be opposite and they make an angle 180 degrees apart.

∴

W = -2 × 7.00 × 1590

W = -22260 J

W = -22.3 kJ

8 0
3 years ago
Add the following forces: 20 Newtons south, 30 newtons north, 40 newtons east, and 50 newtons west
Roman55 [17]

The north and south forces have no effect on the east and west forces.
We can handle the two groups separately.

                       (20N south)  +  (30N north)

                   =  (20N south)  +  (20N north + 10N north)

                   =                              10N north .


                       (40N east)  +  (50N west)

                   =  (40N east)  +  (40N west + 10N west)

                   =                              10N west .
5 0
3 years ago
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