Answer:
970 kN
Explanation:
The length of the block = 70 mm
The cross section of the block = 50 mm by 10 mm
The tension force applies to the 50 mm by 10 mm face, F₁ = 60 kN
The compression force applied to the 70 mm by 10 mm face, F₂ = 110 kN
By volumetric stress, we have that for there to be no change in volume, the total pressure applied by the given applied forces should be equal to the pressure removed by the added applied force
The pressure due to the force F₁ = 60 kN/(50 mm × 10 mm) = 120 MPa
The pressure due to the force F₂ = 110 kN/(70 mm × 10 mm) = 157.142857 MPa
The total pressure applied to the block, P = 120 MPa + 157.142857 MPa = 277.142857 MPa
The required force, F₃ = 277.142857 MPa × (70 mm × 50 mm) = 970 kN
Answer:
5 meters per second
Explanation:
5m is the distance
5m west is the vector
5m per second is the velocity
5m per second west is unknown
The speed of the sound in the xenon is 178 m/s. And the right option is b 178 m/s
<h3 /><h3>What is speed?</h3>
Speed can be defined as the ratio of the total distance traveled by a body to the total time taken.
To calculate the speed of the sound in the xenon, we use the formula below.
Formula:
- v = λf............. Equation 1
Where:
- v = Speed of the sound in xenon
- f = Frequency
- λ = Wavelength.
From the question,
Given:
- f = 440 Hz
- λ = 40.4 cm = 0.404 m
Substitute the values above into equation 1
- v = 440(0.404)
- v = 177.76 m/s.
- v ≈ 178 m/s
Hence, The speed of the sound in the xenon is 178 m/s. And the right option is b 178 m/s
Learn more about speed here: brainly.com/question/4931057
Answer:
no.
Explanation:
because the mass of an object never changes.
