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3 years ago

7.45÷.5please show you got in long division

Mathematics

1 answer:

Lana71 [14]3 years ago

3 0

14.9 would be your answer if you divide by .5 it could go into 7 14 times while in the .45 just 9

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D/dx 3^x= Find the derivative

gregori [183]

Differentiate using the exponential rule, which determines that $\bf{\frac{d}{dx}[a^{x}] }$ is $\bf{a^{x} \ In(a) }$ when a=3.

$\boldsymbol{ 3^{x} \ In(3) \ \to \ \ \ Answer }$

Therefore, the correct option is "E". You just have to remove the parentheses.

$\red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}$

4 0

2 years ago

The distance between Anubhav’s school and his house is 45 km. He started from his house for school at 7:00 am and covered 30 km

8_murik_8 [283]

Answer:

45 km/h

Step-by-step explanation:

In the first part of the trip, he already covered 30 km so we can subtract that from the total distance

45 - 30 = 15

This means he has 15 km to go

He also took an hour, or 60 minutes, to get to school. We subtract the time spent of the first part and time spent talking to a friend from the 60 minutes

60 - 35 = 25

25 - 5 = 20

He took 20 minutes to cover the second part of the journey

Speed = distance/time

15/20 = 0.75

He covered 0.75 km per MINUTE

to find it in km/h, we just multiply the number by 60

0.75 x 60 = 45

6 0

3 years ago

Read 2 more answers

(Picture) MULTIPLYING POLYNOMIALS AND SIMPLIFYING EXPRESSIONS PLEASE HELP!!!!

kvv77 [185]

Answer:

Answer: Third option is the right answer.

Step-by-step explanation:

First we the write the expression

$(a+b)(a^{2}+b^{2}-ab)$

Now teacher says that the product of these polynomials will result in the sum of $a^{3}+b^{3}$

Now the teacher ask if we put the value of a = 2x and b = 1 then what will be the expression look like.

$(2x+1)\left [ (2x)^{2}+(1^{2})-(2x)(1)\right ]$

= $(2x+1)(4x^{2}+1-2x)$

So third option is looking like our expression.

3 0

3 years ago

Find f. A) 7.4 B) 8.2 C) 10.5 D) 11.1

tatyana61 [14]

F=72

g=6

------------

$\cos { \left( F \right) } =\frac { { e }^{ 2 }+{ g }^{ 2 }-{ f }^{ 2 } }{ 2eg }$

Therefore:

$\cos { \left( 72 \right) } =\frac { { e }^{ 2 }+{ 6 }^{ 2 }-{ f }^{ 2 } }{ 2\cdot e\cdot 6 } \\ \\ \cos { \left( 72 \right) } =\frac { { e }^{ 2 }+36-{ f }^{ 2 } }{ 12e }$

$\\ \\ 12e\cdot \cos { \left( 72 \right) } ={ e }^{ 2 }+36-{ f }^{ 2 }\\ \\ \therefore \quad { f }^{ 2 }={ e }^{ 2 }-12e\cdot \cos { \left( 72 \right) } +36\\ \\ \therefore \quad f=\sqrt { { e }^{ 2 }-12e\cdot \cos { \left( 72 \right) +36 } } \\ \\ \therefore \quad f=\sqrt { e\left( e-12\cos { \left( 72 \right) } \right) +36 }$

But what is e?

E=76

G=32

g=6

And:

$\frac { e }{ \sin { \left( E \right) } } =\frac { g }{ \sin { \left( G \right) } }$

Which means that:

$\frac { e }{ \sin { \left( 76 \right) } } =\frac { 6 }{ \sin { \left( 32 \right) } } \\ \\ \therefore \quad e=\frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } }$

If you take this value into account, you will discover that f is...

$f=\sqrt { \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } \left( \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } -12\cos { \left( 72 \right) } \right) +36 } \\ \\ \therefore \quad f=10.8\quad \left( 1\quad d.p \right)$

So I would have to say that the answer is approximately (c).

6 0

3 years ago

The figure below shows a line graph and two shaded triangles that are similar:

ella [17]

Answer:

Step-by-step explanation:

h wh I h6j2tbwtbt2byyh3ht36

7 0

3 years ago

Read 2 more answers

7.45÷.5please show you got in long division​

7.45÷.5please show you got in long division