Answer:
The radius of circle B is 6 times greater than the radius of circle A
The area of circle B is 36 times greater than the area of circle A
Step-by-step explanation:
we have
<em>Circle A</em>
The radius of circle A is
-----> the radius is half the diameter
<em>Circle B</em>
Compare the radius of both circles
The radius of circle B is six times greater than the radius of circle A
Remember that , if two figures are similar, then the ratio of its areas is equal to the scale factor squared
All circles are similar
In this problem the scale factor is 6
so
therefore
The area of circle B is 36 times greater than the area of circle A
The answer is 3, because the other two sides are 3 and the angle is 60, so the other angles will have to be 60. That means it is an equilateral triangle.
The conditions are needed to be able to answer the question
2/3 + 1/4 .....common denominator is 12
8/12 + 3/12 =
11/12 <==
The standard equation of an ellipse is:
(x-h)²/a² + (y-k)²/b² = 1
Since the center at the origin, then h = k = 0
The height of this ellipse = 8 units and the width = 4 units, that means the major axis is b (=8) and the minor axis is a (=4)
Then the equation becomes:
x²/16 + y²/64 = 1