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kondaur [170]
3 years ago
13

See how a block and tackle system can increase your mechanical advantage. You will need two broomsticks, a rope, and two helpers

.
A. Give each helper a broom stick and have them stand facing each other holding the broomstick firmly in both hands in a horizontal position. The broomsticks should be at the same level, about two feet apart.

B. Tie one end of the rope to one of the broomsticks. (You may need to have one of your helpers hold the knot firmly in one hand as he or she holds the broomstick to help anchor it.)

C. Wrap the rope around the other broomstick, as in a simple pulley system, and pull on the free end of the rope. Your helpers should resist your pulling. What happens? Can you pull the broomsticks together?

D. Now weave the rope back over the first broomstick, so you have a double pulley. Pull on the free end. What happens now? Can you pull the broomsticks together? What is your mechanical advantage?

E. Try weaving the rope over the broomsticks one or two more times. Describe what happens, and state the mechanical advantage of each situation.

F. Write a summary of what happened and an explanation using the terms:
Physics
1 answer:
nikklg [1K]3 years ago
6 0

Answer:

The mechanical gain of practicing this pulley system is equivalent to the amount of strength applied to the broomsticks. I practiced work times distance and the total distance was 15.

Explanation:

The important mechanical advantage of a pulley is in practicing many pulleys at once. Consolidating various pulleys minimizes the amount of energy required to move an article by improving the amount of cord utilized to raise the article. The amount of string can be obtained by string = original amount of cord x the number of pulleys.

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The distance travelled by the ball that is thrown horizontally from a window that is 15.4 meters high at a speed of 3.01 m/s is 5.34 m

s = ut + 1 / 2 at²

s = Distance

u = Initial velocity

t = Time

a = Acceleration

Vertically,

s = 15.4 m

u = 0

a = 9.8 m / s²

15.4 = 0 + ( 1 / 2 * 9.8 * t² )

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t = 1.77 s

Horizontally,

u = 3.01 m / s

a = 0 ( Since there is no external force )

s = ( 3.01 * 1.77 ) + 0

s = 5.34 m

Therefore, the distance travelled by the ball before hitting the ground is 5.34 m

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