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vovangra [49]
3 years ago
5

Someone help me please, I don't know how to do it :( ​

Physics
1 answer:
elena-14-01-66 [18.8K]3 years ago
3 0

Answer:

fn /2 .3 'in

Explanation:

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Will give Brainliest!! Question attached.
ss7ja [257]

Answer:

im pretty sure it is 3.0 K

Explanation:

8 0
3 years ago
Read 2 more answers
Air escaping out from an air hose at a gas station always feels cool. Why? ​
kati45 [8]

Answer:

The air is contained at a high pressure in the tube. When it escapes from a small orifice, it suddenly expands. A large amount of its heat is absorbed in the process of expansion resulting in considerable fall in its temperature. This is why the escaping air feels cold.

8 0
2 years ago
Net force is the sum of all the forces acting on an object. If a spring balance pulls on a body with a force of 10 N, and fricti
julsineya [31]

Answer:

5N

Explanation:

(25 N - 20 N = 5 N)

3 0
3 years ago
Describe two examples of Newton's First Law of Motion; the motion of an object does not change if the
alexgriva [62]

Answer:

if you slide a hockey puck on ice, it will eventually stop, because of friction on the ice

kite when the wind changes can be described by the first law

Explanation:

if you slide a hockey puck on ice, it will eventually stop, because of friction on the ice

kite when the wind changes can be described by the first law

6 0
2 years ago
A solid circular plate has a mass of 0.25 kg and a radius of 0.30 m. It starts rolling from rest at the top of a hill 10 m long
KATRIN_1 [288]

To solve the problem it is necessary to apply the equations related to the conservation of both <em>kinetic of rolling objects</em> and potential energy and the moment of inertia.

The net height from the point where it begins to roll with an inclination of 30 degrees would be

h=Lsin30

h=10sin30

h=5m

In the case of Inertia would be given by

I = \frac{mR^2}{2}

In general, given an object of mass m, an effective radius k can be defined for an axis through its center of mass, with such a value that its moment of inertia is

I = mk^2

\frac{mR^2}{2}= mk^2

\frac{k^2}{R^2}=\frac{1}{2}

Replacing in Energy conservation Equation we have that

Potential Energy = Kinetic Energy of Rolling Object

mgh = \frac{1}{2}mv^2(1+\frac{k^2}{r^2})

9.8*5=\frac{1}{2}v^2(1+\frac{1}{2})

v^2 (1.5) = 98

v=8.0829m/s

Therefore the correct answer is C.

3 0
3 years ago
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