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insens350 [35]
3 years ago
14

Water is flowing from a garden hose. A child places his thumb to cover most of those outlet, causing a thin jet of high speed wa

ter to emerge. The pressure in the hose just upstream of his thumb is 400 KPa. If the hose is held upward, what is the maximum height that the jet could achieve?

Physics
1 answer:
Oxana [17]3 years ago
3 0

Answer: maximum height= 40.8m

Explanation: shown in the attachment.

Goodluck

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Solutions with ions that react with acids or bases to lessen their effects are fubrefs
Softa [21]

Answer:

Buffers

Explanation:

A buffer solution is a solution containing weak acids and their salts or weak bases and their salts.

A buffer solution is an equilibrium system that resists changes in pH or pOH when a small amount of an acid or base is added hence it is a solution of fairly constant pH value.

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3 years ago
Todo sistema heterogêneo é bifásico
strojnjashka [21]
I don't understand the language.....
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The two forces in each pair can either both act on the same body or they can act on different bodies. The two forces in each pai
Marrrta [24]

Answer:

The correct answer in which peer forces each act in a different body

Explanation:

Newton's law of action and reaction states that the two forces have equal magnitude, but in the opposite direction, each acting on a body. Which creates acceleration in these, if they act in the same body it would be canceled so there would be no movement.

The correct answer in which peer forces each act in a different body

6 0
4 years ago
Based on the following equation, answer the questions below. ρ = (2γϕ + ψ)/rg where ρ [=] moles per cubic foot [mol/ft3] γ [=] j
AlekseyPX

1) Fundamental units of \Psi are [\frac{mol}{m\cdot s^2}]

2) Fundamental units of \Phi are [\frac{mol}{m^3}]

Explanation:

The equation for the variable \rho is

\rho =\frac{2\gamma \Phi+\Psi}{rg}

where we have:

\rho measured in [\frac{mol}{ft^3}]

\gamma measured in [\frac{J}{kg}]

r measured in [in]

g measured in [\frac{m}{s^2}]

We can re-write the equation as

\rho rg = 2\gamma \Phi + \Psi

And we notice that the units of the term on the left must be equal to the units of the term on the right.

This means that:

1) First of all, \Psi must have the same units of \rho r g. So,

[\rho r g]=[\frac{mol}{ft^3}][in][\frac{m}{s^2}]

However, both ft (feet) and in (inches) are not fundamental dimensions: this means that they can be expressed as meters. Therefore, the fundamental units of \Psi are

[\Psi]=[\frac{mol}{m^3}][m][\frac{m}{s^2}]=[\frac{mol}{m\cdot s^2}]

2)

The term 2\gamma \Phi must have the same units of \Psi in order to be added to it. Therefore,

[\gamma \Phi] = [\frac{mol}{m\cdot s^2}]

We also know that the units of \gamma are [\frac{J}{kg}], therefore

[\frac{J}{kg}][\Phi]= [\frac{mol}{m\cdot s^2}]

And so, the fundamental units of \Phi are

[\Phi]= [\frac{mol\cdot kg}{J\cdot m\cdot s^2}]

However, the Joules can be written as

[J]=[kg][\frac{m^2}{s^2}]

Therefore

[\Phi]= [\frac{mol\cdot kg}{(kg \frac{m^2}{s^2})\cdot m\cdot s^2}]=[\Phi]= [\frac{mol}{m^3}]

#LearnwithBrainly

7 0
3 years ago
Mechanical energy is the difference between the kinetic and potential energies of an object. True or False?
Fofino [41]

Answer:

False

Explanation:

Its the sum of those not the difference between them

4 0
4 years ago
Read 2 more answers
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