Water is flowing from a garden hose. A child places his thumb to cover most of those outlet, causing a thin jet of high speed wa
ter to emerge. The pressure in the hose just upstream of his thumb is 400 KPa. If the hose is held upward, what is the maximum height that the jet could achieve?
1 answer:
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Answer:
Two stationary positive point charges, charge 1 of magnitude 3.45 nC and charge 2 of magnitude 1.85 nC, are separated by a distance of 50.0 cm. An electron is released from rest at the point midway between the two charges, and it moves along the line connecting the two charges. What is the speed v(final) of the electron when it is 10.0 cm from
The answer to the question is
The speed of the electron when it is 10.0 cm from charge Q₁
= 7.53×10⁶ m/s
Explanation:
To solve the question we have
Q₁ = 3.45 nC = 3.45 × 10⁻⁹C
Q₂ = 1.85 nC = 1.85 × 10⁻⁹ C
2·d = 50.0 cm
a = 10.0 cm
q = -1.6×10⁻¹⁹C
Also initial kinetic energy = 0 and
Initial electric potential energy =
Final kinetic energy due to motion = 0.5·m·v²
Final electric potential energy =
From the energy conservation principle we have
Solving for v gives
where k = 9.0×10⁹ and m = 9.109×10⁻³¹ kg
gives v =7528188.32769 m/s or 7.53×10⁶ m/s
= 7.53×10⁶ m/s
Answer:
9.8 m/s
Explanation:
The work done by the force pushing the cart is equal to the kinetic energy gained by the cart:
where
W is the work done
is the final kinetic energy of the cart
is the initial kinetic energy of the cart, which is zero because the cart starts from rest, so we can write:
But the work is equal to the product between the pushing force F and the displacement, so
So, the final kinetic energy of the cart is 480 J. The formula for the kinetic energy is
(1)
where m is the mass of the cart and v its final speed.
We can find the mass because we know the weight of the cart, 98.0 N:
Therefore, we can now re-arrange eq.(1) to find the final speed of the cart: