I’d think the answer would be C. i’m just kinda guessing but my thought process is this (as simply as i can put it because physics is confusing):
so for example say you throw a ball across a flat surface. inertia is what keeps the ball rolling straight in a line, so unless you were to maybe put your hand in front of the ball or something, it would just go straight forever.
this is what happens with the planets. they go in a straight line, but since there’s gravity, the planets are also being pulled towards the sun. so gravity and inertia are why the planets orbit in the circle pattern they do. so when we remove inertia, we’re removing the state in which the planets keep going straight while being pulled towards a center point (the sun). this causes gravity to be the only factor in the planets orbiting. so that being said, the planets would just be pulled towards the sun. :)
Answer:
It has been converted into thermal energy due to friction
Explanation:
According to the law of conservation of energy, energy cannot be created nor destroyed, but only transformed from one form into another.
Applied to this problem, it means that the total initial energy of the spring-toy system must be conserved.
Therefore:
- At the beginning, the total energy stored in the spring is 10 J
- After the toy is released, the total energy must still be 10 J.
In reality, we are told that the kinetic energy of the car is only 8 J. The other 2 J have not been destroyed, but they have been converted into thermal energy, due to the presence of frictional forces that act against the motion of the toy car.
From the calculations, the value of the acceleration due to gravity is 0.38 m/s^2.
<h3>What is weight?</h3>
The weight of an object is obtained as the product of the mass of the body and the acceleration due to gravity.
Thus;
When;
mass = 120 kg
weight = 46 N
acceleration due to gravity = 46 N/120 kg
=0.38 m/s^2
Learn more about acceleration due to gravity :brainly.com/question/13860566
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It increases, because the centripetal acceleration is inversely proportional to the radius of the curvature.
Hopr it helps :)