Permeable materials for what
Below is the list of both Natural and Synthetic compounds containing Carbon.
Natural Compounds Containing Carbon:
1) Food:
Carbohydrates, Proteins, Lipids, Fibers
2) Clothing:
Silk, Wool, Cotton
3) Transportation:
Coal, Natural Gas, Petroleum
4) Wood:
Building, Furniture
Synthetic Compounds Containing Carbon:
1) Clothing:
Nylon, Polyester,
2) Transportation:
Petrol, Diesel, Jet Fuels
3) Building:
High Density Polyethylene, Polyvinyl Chloride
4) Home Appliances:
Teflon in non-stick Pans, polyethylene terephthalate bottles
<u>Answer:</u> The mass percent of ethylene glycol in solution is 14.2 %
<u>Explanation:</u>
We are given:
Molarity of ethylene glycol solution = 2.45 M
This means that 2.45 moles of ethylene glycol is present in 1 L or 1000 mL of solution.
- To calculate the mass of solution, we use the equation:
![\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}](https://tex.z-dn.net/?f=%5Ctext%7BDensity%20of%20substance%7D%3D%5Cfrac%7B%5Ctext%7BMass%20of%20substance%7D%7D%7B%5Ctext%7BVolume%20of%20substance%7D%7D)
Density of solution = 1.07 g/mL
Volume of solution = 1000 mL
Putting values in above equation, we get:
![1.07g/mL=\frac{\text{Mass of solution}}{1000mL}\\\\\text{Mass of solution}=(1.07g/mL\times 1000mL)=1070g](https://tex.z-dn.net/?f=1.07g%2FmL%3D%5Cfrac%7B%5Ctext%7BMass%20of%20solution%7D%7D%7B1000mL%7D%5C%5C%5C%5C%5Ctext%7BMass%20of%20solution%7D%3D%281.07g%2FmL%5Ctimes%201000mL%29%3D1070g)
- To calculate the number of moles, we use the equation:
![\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3D%5Cfrac%7B%5Ctext%7BGiven%20mass%7D%7D%7B%5Ctext%7BMolar%20mass%7D%7D)
Moles of ethylene glycol = 2.45 moles
Molar mass of ethylene glycol = 62 g/mol
Putting values in above equation, we get:
![2.45mol=\frac{\text{Mass of ethylene glycol}}{62g/mol}\\\\\text{Mass of ethylene glycol}=(2.45mol\times 62g/mol)=151.9g](https://tex.z-dn.net/?f=2.45mol%3D%5Cfrac%7B%5Ctext%7BMass%20of%20ethylene%20glycol%7D%7D%7B62g%2Fmol%7D%5C%5C%5C%5C%5Ctext%7BMass%20of%20ethylene%20glycol%7D%3D%282.45mol%5Ctimes%2062g%2Fmol%29%3D151.9g)
- To calculate the mass percentage of ethylene glycol in solution, we use the equation:
![\text{Mass percent of ethylene glycol}=\frac{\text{Mass of ethylene glycol}}{\text{Mass of solution}}\times 100](https://tex.z-dn.net/?f=%5Ctext%7BMass%20percent%20of%20ethylene%20glycol%7D%3D%5Cfrac%7B%5Ctext%7BMass%20of%20ethylene%20glycol%7D%7D%7B%5Ctext%7BMass%20of%20solution%7D%7D%5Ctimes%20100)
Mass of solution = 1070 g
Mass of ethylene glycol = 151.9 g
Putting values in above equation, we get:
![\text{Mass percent of ethylene glycol}=\frac{151.9g}{1070g}\times 100=14.2\%](https://tex.z-dn.net/?f=%5Ctext%7BMass%20percent%20of%20ethylene%20glycol%7D%3D%5Cfrac%7B151.9g%7D%7B1070g%7D%5Ctimes%20100%3D14.2%5C%25)
Hence, the mass percent of ethylene glycol in solution is 14.2 %
The mass of carbon monoxide present in the room is 0.006502 g.
<h3>What is Density?</h3>
Density is the mass of a substance per unit volume.
![\rho = \frac{m}{V}](https://tex.z-dn.net/?f=%5Crho%20%3D%20%5Cfrac%7Bm%7D%7BV%7D)
Where
ρ = density of the substance
m = mass of the substance and
V = volume of the substance
Here, ρ = 48 μg/m³
Volume = 13 ft x 13.5 ft x 19.5 ft
1 ft = 0.3408 m
V = (13 x 0.3408 m) x (13.5 x 0.3408 m) x (19.5 x 0.3408 m)
= 135.46 m³
m = ρ x V
= 48 μg/m³ x 135.46 m³
= 6502.08 μg
= 6502.08 x 10⁻⁶ g
=0.006502g
Hence, The mass of carbon monoxide present in the room is 0.006502 g.
Learn more about Density:
brainly.com/question/6838128
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Then it will blow or make a big eruption then you might die