Answer:
75.15 mol.
Explanation:
- Firstly, we need to write the balanced equation of the reaction:
<em>Fe₂O₃ + 3CO → 2Fe + 3CO₂.</em>
It is clear that 1.0 mole of Fe₂O₃ reacts with 3.0 moles of CO to produce 2.0 moles of Fe and 3.0 moles of CO₂.
∴ Fe₂O₃ reacts with CO with (1: 3) molar ratio.
- we need to calculate the no. of moles of (4000 g) of Fe₂O₃:
<em>no. of moles of Fe₂O₃ = mass/molar mass</em> = (4000 g)/(159.69 g/mol) = <em>25.05 mol.</em>
<u>Using cross multiplication:</u>
1.0 mole of Fe₂O₃ needs → 3.0 moles of CO,
∴ 25.05 mole of Fe₂O₃ needs → ??? moles of CO.
<em>∴ The no. of moles of CO needed</em> = (3.0 mol)(25.05 mol)/(1.0 mol) =<em> 75.15 mol.</em>
Answer:
The answer is 102.3!
Explanation:
you get this by multiplying 34.1 x 3 to get 102.3.
Wondering why you multiply 34.1 times 3?
WELLLLLLLLLLL...
when you get 1 mole of h202, you get 34.1 so if you ask for 3 moles of H202, you get 102.3!
There are three elements hydrogen, chlorine, and oxygen
Fe2(SO4)3 + 6KOH -> 3K2SO4 + 2Fe(OH)3
