Answer:
B. x(x) + (−6)(−3)
NOT equivalent to (x − 6)(x − 3)
Step-by-step explanation:
(x − 6)(x − 3)
= x^2 - 3x - 6x + 18
= x^2 - 9x + 18
A. (6 − x)(3 − x)
= 18 - 6x - 3x + x^2
= 18 - 9x + x^2
= x^2 - 9x + 18 ---->equivalent to (x − 6)(x − 3)
B. x(x) + (−6)(−3) = x^2 + 18 ----> NOT equivalent to (x − 6)(x − 3)
C. x2 − 3x − 6x + 18 = x^2 - 9x + 18 --> equivalent to (x − 6)(x − 3)
D. x(x − 6) − 3(x − 6)
= x^2 - 6x - 3x + 18
= x^2 - 9x + 18 ---->equivalent to (x − 6)(x − 3)
36m^2 is the your answer hope it help
For this question, all you have to do is subtract 6 from 10 to get 4. 4 + 6 is 10. z = 4.
The maximum value attained by the function will be 4
4 = 4cos(2x - π)
cos(2x - π) = 1
2x - π = 0
x = (nπ)/2
From x = 0 to x = 2π, n = 1, 2, etc
The equation will yield +4 for odd values of n and -4 for even values of n
