Since hex means 6 from Greek, the answer is D) SF6
Answer:
322 kJ
Explanation:
The work is the energy that a force produces when realizes a displacement. So, for a gas, it occurs when it expands or when it compress.
When the gas expands it realizes work, so the work is positive, when it compress, it's suffering work, so the work is negative.
For a constant pressure, the work can be calcutated by:
W = pxΔV, where W is the work, p is the pressure, and ΔV is the volume variation. To find the work in Joules, the pressure must be in Pascal (1 atm = 101325 Pa), and the volume in m³ (1 L = 0.001 m³), so:
p = 60 atm = 6.08x10⁶ Pa
ΔV = 82.0 - 29.0 = 53 L = 0.053 m³
W = 6.08x10⁶x0.053
W = 322x10³ J
W = 322 kJ
Answer:
the value of vA that will allow the car to coast in neutral so as to just reach the top of the 150 m high hill at B with vB = 0 is 31.3 m/s
Explanation:
given information
car's mass, m = 1200 kg
= 100 m
= 
= 150 m
= 0
according to conservative energy
the distance from point A to B, h = 150 m - 100 m = 50 m
the initial speed 
final speed
= 0
thus,
² =
² - 2 g h
0 =
² - 2 g h
² = 2 g h
= √2 g h
= √2 (9.8) (50)
= 31.3 m/s
The magnitude of the friction on the cart is 28,56 N
To measure the deceleration of a car, without the value of the time of the movement, the <u>Torricelli equation</u> is used, which consists of:

Where is final velocity, is initial velocity, is acceleration, and is displacement.
Now, substitute the values in the formula:




Finally, the value of the acceleration found is multiplied by the mass of the object, thus measuring the friction force:


Learn more about friction force at: brainly.com/question/13707283
Explanation:
It is given that,
Mass of the car, m = 875 kg
Initial speed of the car, u = 30 m/s
Brakes are applied i.e. v = 0
The car skids for 5.60 s in the positive x - direction before coming to rest, t = 5.6
(a) Acceleration of the car, 


(b) Force, F = ma

F = -4681.25 N
So, the force of 4681.25 N is acting on the car.
(c) Let x is the distance covered by the car. So,




x = 84.11 meters
So, the distance covered by the car is 84.11 meters. Hence, this is the required solution.