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almond37 [142]
3 years ago
6

Plz i need help im stuck

Physics
1 answer:
iVinArrow [24]3 years ago
4 0

Answer:

Refraction makes the apple seem to be in a different location.

You might be interested in
Sulfur hexafluoride is represented by which formula? A) sf2 b) sf7 c) s2f5 d) sf6
Margarita [4]
Since hex means 6 from Greek, the answer is D) SF6
4 0
3 years ago
Read 2 more answers
A mixture of helium and argon gas is expanded from a volume of 29.0L to a volume of 82.0L, while the pressure is held constant a
finlep [7]

Answer:

322 kJ

Explanation:

The work is the energy that a force produces when realizes a displacement. So, for a gas, it occurs when it expands or when it compress.

When the gas expands it realizes work, so the work is positive, when it compress, it's suffering work, so the work is negative.

For a constant pressure, the work can be calcutated by:

W = pxΔV, where W is the work, p is the pressure, and ΔV is the volume variation. To find the work in Joules, the pressure must be in Pascal (1 atm = 101325 Pa), and the volume in m³ (1 L = 0.001 m³), so:

p = 60 atm = 6.08x10⁶ Pa

ΔV = 82.0 - 29.0 = 53 L = 0.053 m³

W = 6.08x10⁶x0.053

W = 322x10³ J

W = 322 kJ

8 0
3 years ago
A 1200 kg car reaches the top of a 100 m high hill at A with a speed vA. What is the value of vA that will allow the car to coas
SVEN [57.7K]

Answer:

the value of vA that will allow the car to coast in neutral so as to just reach the top of the 150 m high hill at B with vB = 0 is 31.3 m/s

Explanation:

given information

car's mass, m = 1200 kg

h_{A} = 100 m

v_{A} = v_{A}

h_{B} = 150 m

v_{B} = 0

according to conservative energy

the distance from point A to B, h = 150 m - 100 m = 50 m

the initial speed v_{A}

final speed  v_{B} = 0

thus,

v_{B}² = v_{A}² - 2 g h

0 = v_{A}² - 2 g h

v_{A}² = 2 g h

v_{A} = √2 g h

    = √2 (9.8) (50)

    = 31.3 m/s

8 0
3 years ago
A shopping cart is pushed and released,
Wewaii [24]

The magnitude of the friction on the cart is 28,56 N

To measure the deceleration of a car, without the value of the time of the movement, the <u>Torricelli equation</u> is used, which consists of:

                                  {\displaystyle {v_{f}}^{2}={v_{o}}^{2}+2a\Delta s}

Where is final velocity, is initial velocity, is acceleration, and is displacement.

Now, substitute the values ​​in the formula:

                                   0^{2} = (3.5)^{2} + 2a6

                                    0 = 12.25 + 12a

                                          a = -\frac{12.25}{12}

                                           a = -1.02

Finally, the value of the acceleration found is multiplied by the mass of the object, thus measuring the friction force:

                                        F = 28\times-1.02

                                         F = -28.56 N

Learn more about friction force at: brainly.com/question/13707283

5 0
3 years ago
A car of mass 875 kg is traveling 30.0 m/s when the driver applies the brakes, which lock the wheels. The car skids for 5.60 s i
AleksAgata [21]

Explanation:

It is given that,

Mass of the car, m = 875 kg

Initial speed of the car, u = 30 m/s

Brakes are applied i.e. v = 0

The car skids for 5.60 s in the positive x - direction before coming to rest, t = 5.6

(a) Acceleration of the car, a=\dfrac{v-u}{t}

a=\dfrac{0-30}{5.6}

a=-5.35\ m/s^2

(b) Force, F = ma

F=875\ kg\times -5.35\ m/s^2

F = -4681.25 N

So, the force of 4681.25 N is acting on the car.

(c) Let x is the distance covered by the car. So,

v^2-u^2=2ax

0-u^2=2ax

x=\dfrac{-u^2}{2a}

x=\dfrac{-(30\ m/s)^2}{2\times -5.35\ m/s^2}

x = 84.11 meters

So, the distance covered by the car is 84.11 meters. Hence, this is the required solution.

7 0
3 years ago
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