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Katyanochek1 [597]
3 years ago
5

How many grams of HNO3 are produced when 60.0 g of NO2 completely reacts?

Chemistry
1 answer:
olganol [36]3 years ago
3 0
<h3>Answer:</h3>

54.756 g

<h3>Explanation:</h3>

Assuming the equation for the reaction in question;

3NO₂(g) + H₂O(l) → 2HNO₃(aq) + NO(g)

We are given;

  • Mass of NO₂ as 60.0 g

We are required to calculate the mass of HNO₃ produced

  • We can calculate the mass of HNO₃ produced using the following simple steps;
<h3>Step 1: Calculate the moles of NO₂</h3>

Moles = Mass ÷ Molar mass

Molar mass of NO₂ = 46.01 g/mol

Therefore;

Moles of NO₂ = 60.0 g ÷ 46.01 g/mol

                       = 1.304 moles

<h3>Step 2: Calculate the moles of HNO₃ produced </h3>

From the equation, 3 moles of NO₂ reacted to produce 2 mole of HNO₃

Therefore, the mole ratio of NO₂ to HNO₃ is 3 : 2

Thus;

Moles of HNO₃ = Moles of NO₂ × 2/3

                          = 1.304 moles × 2/3

                          = 0.869 Moles

<h3>Step 3: Calculate the mass of HNO₃</h3>

Mass = Moles × Molar mass

Molar mass of HNO₃ = 63.01 g/mol

Therefore;

Mass = 0.869 moles × 63.01 g/mol

         = 54.756 g

Thus, the mass of HNO₃ produced is 54.756 g

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Answer:

C.) A generator transforms mechanical energy into electrical energy with the help of static electricuty

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they convert mechanical or chemical energy into electrical energy. They do this by capturing the power of motion and turning it into electrical energy by forcing electrons from the external source through an electrical circuit.

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5 0
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A
BARSIC [14]

The number of C atoms in 0.524 moles of C is 3.15 atoms.

The number of SO_2 molecules in 9.87 moles  SO_2 is 59.43 molecules.

The moles of Fe in 1.40 x 10^{22} atoms of Fe is 0.23 x 10^{-1}

The moles of C_2H_6O in 2.30x10^{24} molecules of C_2H_6O is 3.81.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 × 10^{23} of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

A. The number of C atoms in 0.524 mole of C:

6.02214076 × 10^{23} x 0.524 mole

3.155601758 atoms =3.155 atoms

B. The number of SO_2 molecules in 9.87 moles of SO_2:

6.02214076 × 10^{23} x 9.87

59.4385293 molecules= 59.43 molecules

C. The moles of Fe in 1.40 x 10^{22} atoms of Fe:

1.40 x 10^{22} ÷ 6.02214076 × 10^{23}

0.2324754694 x 10^{-1} moles.

0.23 x 10^{-1} moles.

D. The moles of C_2H_6O in 2.30x10^{24} molecules of C_2H_6O:

2.30x10^{24} ÷ 6.02214076 × 10^{23}

3.819239854 moles=3.81 moles

Learn more about moles here:

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URGENT!!! What is the balanced form of this equation?
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To balance out the H^+ on the reactant side, we write H_2O on the product side.

Balancing out the following reaction gives us:

2MnO_4^-+6H^++5H_2O_2\rightarrow 2Mn^{2+}+8H_2O+5O_2

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Which of the following will increase solubility the rate of the dissolving process of a gaseous solute in solvent? (mark all tha
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Answer: The increase in solubility or the rate of dissolving process of a gaseous solute in a liquid solvent is due to following:

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  • Increasing temperature
  • Increasing solute's partial pressure over the solvent
  • Increasing solute's surface area

Explanation:

When agitation is increased then there will occur an increase in kinetic energy of the molecules of a substance. As a result, more number of collisions will take place due to which more amount of solute will dissolve into the solvent.

Similarly, increasing the temperature will further increase the kinetic energy of molecules. Hence, this will lead to more solubility of gaseous solute into the liquid solvent.

As solubility of a gas is directly proportional to the pressure of the gas above surface of the solution. So, an increase in solute's partial pressure over solvent will also lead to an increase in solubility of gaseous solute into liquid solvent.

When surface area of solute is increased then there will be more solute particles available for reaction. Hence, more collisions will take place. As a result, rate of reaction is more due to which there will be an increase in solubility.

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