Which statement below correctly describes what changes when moving downwards from fluorine to chlorine on the periodic table?

Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a tank

Masja [62]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The concentration equilibrium constant is $K_c = 14.39$

Explanation:

The chemical equation for this decomposition of ammonia is

$2 NH_3$ ↔ $N_2 + 3 H_2$

The initial concentration of ammonia is mathematically represented a

$[NH_3] = \frac{n_1}{V_1} = \frac{29}{75}$

$[NH_3] = 0.387 \ M$

The initial concentration of nitrogen gas is mathematically represented a

$[N_2] = \frac{n_2}{V_2}$

$[N_2] = 0.173 \ M$

So looking at the equation

Initially (Before reaction)

$NH_3 = 0.387 \ M$

$N_2 = 0 \ M$

$H_2 = 0 \ M$

During reaction(this is gotten from the reaction equation )

$NH_3 = -2 x$ (this implies that it losses two moles of concentration )

$N_2 = + x$ (this implies that it gains 1 moles)

$H_2 = +3 x$ (this implies that it gains 3 moles)

Note : x denotes concentration

At equilibrium

$NH_3 = 0.387 -2x$

$N_2 = x$

$H_2 = 3 x$

Now since

$[NH_3] = 0.387 \ M$

$x= 0.387 \ M$

$H_2 = 3 * 0.173$

$H_2 = 0.519 \ M$

$NH_3 = 0.387 -2(0.173)$

$NH_3 = 0.041 \ M$

Now the equilibrium constant is

$K_c = \frac{[N_2][H_2]^3}{[NH_3]^2}$

substituting values

$K_c = \frac{(0.173) (0.519)^3}{(0.041)^2}$

$K_c = 14.39$

3 0

3 years ago

Describe how you would prepare approximately 2 l of 0.050 0 m boric acid, b(oh)3.

Elenna [48]

The given concentration of boric acid = 0.0500 M

Required volume of the solution = 2 L

Molarity is the moles of solute present per liter solution. So 0.0500 M boric acid has 0.0500 mol boric acid present in 1 L solution.

Calculating the moles of 0.0500 M boric acid present in 2 L solution:

$2 L * \frac{0.0500 mol B(OH)_{3} }{1 L} = 0.100 mol B(OH)_{3}$

Converting moles of boric acid to mass:

$0.100 mol B(OH)_{3} * \frac{61.83 g}{mol B(OH)_{3}} = 6.183 g$

Therefore, 6.183 g boric acid when dissolved and made up to 2 L with distilled water gives 0.0500 M solution.

5 0

3 years ago

How are elements and compounds are different

navik [9.2K]

AN element is composed from atoms with the same number of protons,
A compound contain two or more different elements

8 0

3 years ago

Describe the environmental impacts that are involved during the design, research and development, and marketing phases of cell p

Debora [2.8K]

Answer:

joe mama

Explanation:

400 + 20 + 420

4 0

3 years ago

The sheet of gold foil Rutherford used was 304 mm wide and 0.016 mm thick. What maximum length of gold foil could be made from 1

katrin [286]

The maximum length of gold foil could be 1171.7 cm made from 1.10 x 10³ g of gold.

<h3>What is the density?</h3>

The density of an object can be described as the mass per unit volume. The average density is equal to the total mass divided by its total volume.

The mathematical formula of the density of the material can be expressed as follows:

Density = Mass/Volume

The density of a substance is an intrinsic property as it doesn't depend on its size and the S.I. unit of the density is Kg/m³.

Given the width of the gold foil, w = 304 mm = 30.4 cm

The height or thickness of the foil, h = 0.016 mm = 0.0016 cm

The density of the gold foil, d = 19.3 g/cm³

The mass of the gold given, m = 1100 g

The volume of the foil = m/d = 1100/ 19.3 = 56.99 g/cm³

As we know that the volume of gold foil , V = l × w × h

l = V/(w × h)

l = 56.99/(30.4 × 0.0016)

l =1171.7 cm

Learn more about density, here:

brainly.com/question/15164682

#SPJ1

8 0

1 year ago