1.50 moles of argon are at a pressure of 4.125 atm and a temperature of -38.0 degrees C. What is the volume of the sample?
1 answer:
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Answer : The molarity after a reaction time of 5.00 days is, 0.109 M
Explanation :
The integrated rate law equation for second order reaction follows:
where,
k = rate constant =
t = time taken = 5.00 days
[A] = concentration of substance after time 't' = ?
= Initial concentration = 0.110 M
Now put all the given values in above equation, we get:
Hence, the molarity after a reaction time of 5.00 days is, 0.109 M
<h2>ANSWER OF EACH PART ARE GIVEN BELOW</h2>
Explanation:
A)
We know, each mole contains
atoms.
It is given that mass of one oxygen atom is m= .
Therefore, mass of one mole of oxygen, .
Putting value of n and ,
B)
Given,
Mass of water in glass=0.050 kg = 50 gm.
From above part mass of one mole of oxygen atoms = 16.0 gm.
Therefore, number of mole of oxygen equivalent to 50 gm oxygen
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Avogadro's number