The % yield if 200g of chlorine react with excess Potassium bromide to produce 410g of bromine is calculated as below
% yield = actual yield/theoretical yield x100
the actual yield = 410 grams
calculate the theoretical yield
by first calculate the moles of chlorine used
mole= mass/molar mass
molar mass of Cl2 = 35.5 x2= 71 g/mol
moles= 200g/71g/mol = 2.82 moles
cl2 +2 KBr = 2KCl +Br2
by use of mole ratio between Cl2 to Br2 which is 1:1 the moles of Br2 is also = 2.82 moles
theoretical mass = moles x molar mass
molar mass of Br2= 79.9 x2= 159.8 g/mol
moles= 2.82g x 159.8 g/mol = 450.64 grams
% yield is therefore = 410g/450.64 x100 = 90.98 %
Answer:
So that if we feel weak, energy is released through it so we can do work and do stuff like walk or think. It's like stored energy that can do things for the future.
Please give brainliest if it helped.
Responder:
2H2 + O2 → 2H2O
CaO + H2O → Ca (OH) 2
Fe + S → FeS
H2SO3 → SO2 + H2O
CaCO3 → CaO + CO2
Explicación:
2H2 + O2 → 2H2O
2 moléculas de hidrógeno gaseoso reaccionan con oxigente para producir 2 moléculas de agua
CaO + H2O → Ca (OH) 2
El óxido de calcio reacciona con el agua para producir hidróxido de calcio.
Fe + S → FeS
El hierro reacciona con el azufre para producir sulfuro de hierro.
H2SO3 → SO2 + H2O
Por descomposición, el ácido sulfuroso se descompone para producir dióxido de azufre y agua.
CaCO3 → CaO + CO2
El carbonato de calcio se descompone para producir óxido de calcio y dióxido de carbono.
Answer:
QP
Explanation:
P has 9 electrons.
Electronic Configuration : 2, 7
Valence electrons : 7
P needs 1 electron to get stable electronic configuration.
Q has 3 electrons.
Electronic Configuration : 2, 1
Valence electrons : 1
P needs to loose 1 electron to get stable electronic configuration.
Q donates 1 electron,
Q -----> Q+ + 1 e-
P gains 1 electron,
P + 1 e- -----> P-
Q+ + P- -----> QP
This is an ionic compound.
Answer:
The answer to your question is D