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Alika [10]
3 years ago
15

How can criteria be used to help define the problem?

Chemistry
1 answer:
Andre45 [30]3 years ago
4 0

Answer:

It helps get you to the proof of the matter

Explanation:

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ANSWER QUICK PLEASE <br> WORTH 100 POINTS
sukhopar [10]

Answer:

Explanation:

Volume is defined as the space occupied by an object or substance irrespective of its state of matter.The conversion used from millimeter to liter is:

1 milliiliter = 0.001 L

Therefore, we can convert the volume of sample from 2.5 ml in liters as follows.

2.5 ml in liters = 2.5ml x 0.001 L/1ml

= 0.0025 L

Thus, we can conclude that the volume of given sample in liter is 0.0025 L

Hope this helps! :)

6 0
3 years ago
How long does it take the Earth to move from Point A to Point C?
e-lub [12.9K]

Answer:

24 hours

Explanation:

8 0
3 years ago
Read 2 more answers
What is the mass percent of oxygen (0) in SO2?
vazorg [7]

Answer:

D. (16.0 g + 16.0 g) × 100% / (32.1 g + 16.0 g + 16.0 g) = 49.9%

Explanation:

Step 1: Detemine the mass of O in SO₂

There are 2 atoms of O in 1 molecule of SO₂. Then,

m(O) = 2 × 16.0 g = 16.0 g + 16.0 g = 32.0 g

Step 2: Determine the mass of SO₂

m(SO₂) = 1 × mS + 2 × mO = 1 × 32.1 g + 2 × 16.0 g = 32.1 g + 16.0 g + 16.0 g = 64.1 g

Step 3: Detemine the mass percent of oxygen in SO₂

We will use the following expression.

m(O)/m(SO₂) × 100%

(16.0 g + 16.0 g) × 100% / (32.1 g + 16.0 g + 16.0 g) = 49.9%

5 0
3 years ago
45.7 grams of calcium chloride reacts with an excess of aluminum oxide. How many grams of aluminum chloride will be produced
damaskus [11]
Molar mass (CaCl2) = 40.1 +2*35.5 = 111.1 g/mol
Molar mass (AlCl3) = 27.0 +3*35.5= 133.5 g/ mol

                                               
3CaCl2+Al2O3 -------->3CaO +2AlCl3
mole from reaction              3 mol                                              2 mol
mass from reaction         3mol* 111.1g/mol                             2 mol*133.5g/mol
                                               333.3 g                                            267.0 g
mass from problem              45.7 g                                               x g

Proportion:
  333.3 g  CaCl2  -------   267.0 g AlCl3
  45.7 g   CaCl2   --------   x g    AlCl3

x=45.7*267.0/333.3= 36.6 g AlCl3
5 0
3 years ago
why are plasmas of great interest to scientists or manufacturers. descride 2 current uses of plasmas and describe 1 way scientis
Helga [31]

<u>Answer:</u>

<u>Plasmas of great interest to scientists or manufacturers as</u>

  • Plasma is electrically charged gases that contain considerable charged particles that can change the behavior of the substance.

<u>Current uses of plasmas:</u>

  • First, it is used to make semiconductors for different types of electronic equipment
  • Secondly, they're used in making transmitters for high-temperature films.

<u>Way scientists and engineers hope to use plasmas in the future:</u>

  • The scientists are hoping to use plasma in the future to get rid of all hazardous wastes through a process called plasma gasification.

6 0
3 years ago
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