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Softa [21]
3 years ago
10

Calculate the kinetic energy of Julie, a 60 kg biker, traveling at a velocity of 8 m/s to the right

Physics
1 answer:
Vadim26 [7]3 years ago
8 0

Answer:

1,920 Joules

Explanation:

K.E. = 1/2  mv2

so  K.E. =  1/2 (60)(8x8) = 1,920 Joules

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A uniform magnetic field of magnitude 0.23 T is directed perpendicular to the plane of a rectangular loop having dimensions 7.8
Arlecino [84]

Answer:

0.0025116weber/m²

Explanation:

Magnetic field density (B) is the ratio of the magnetic flux (¶) through the loop to its cross sectional area (A).

Mathematically;

B = ¶/A

¶ = BA

Given B = 0.23Tesla which is the magnitude of the magnetic field

Dimension of the rectangular loop = 7.8 cm by 14 cm

Area of the rectangular loop perpendicular to the field B = 7.8cm×14cm

= 109.2cm²

Converting this value to m²

Area of the loop = 109.2 × 10^-4

Area of the loop = 0.01092m²

Magneto flux = 0.23×0.01092

Magnetic flux = 0.0025116weber/m²

3 0
3 years ago
Read 2 more answers
What is physics? In your own words too
denis23 [38]
The study of how the world works
4 0
3 years ago
Describe the gravity and magnetic separation technique using sand as an example​
Svet_ta [14]

Answer:

Gravity separation is an industrial method of separating two components, either a suspension, or dry granular mixture where separating the components with gravity is sufficiently practical: i.e. the components of the mixture have different specific materials and Magnetic separations take advantages of natural magnetic properties between minerals in feed. The separation is between economic ore constituents, noneconomic contaminants and gangue. and saw dust can be separated by gravity separation method. The process can be used for separating insoluble substances which are heavier than liquid by allowing them to settle down on their own due to gravity. The mixture of sand and iron can be separated from each other by using a magnet. Iron gets attracted towards a magnet leaving behind the sand.

<h2>Please mark me as brainliest by clicking on the crown at the bottom of my answer</h2>

4 0
2 years ago
A proton is released from rest at the origin in a uniform electric field in the positive x direction with magnitude 850 N/C. Wha
Gwar [14]

A proton is released from rest at the origin in a uniform electric field in the positive x direction with magnitude 850 N/C. The change in the electric potential energy of the proton-field system when the proton travels to x = 2.50m is -3.40 × 10⁻¹⁶ J (Option B)

<h3 /><h3>How is the change in electric potential energy of the proton-field system calculated?</h3>

  • Work done on the proton =Negative of the change in the electric potential energy of the proton field
  • In the given case, W = -qΔV
  • -W = qΔV
  • = qEcosθ
  • Therefore, work done on the proton = -e(8.50×10^2 N/C)(2.5m)(1)
  • = -3.40×10^-^1^6 J
  • Any change in the potential energy indicates the work done by the proton.
  • Therefore the positive sign shows that the potential energy increases when the proton does the work.
  • The negative sign shows that the potential energy decreases when the proton does the work.

To learn more about electric potential energy, refer

brainly.com/question/14306881

#SPJ4

3 0
1 year ago
how to draw a labelled diagram of earth's magnetic field ,show how the solar wind distorts the magnetic field ​
Ann [662]

Answer:

dkdnfbbd

kejdjjdjdjksolalskdhbdhdh

Explanation:

ndndbcbnf

4 0
3 years ago
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