A planet is in circular orbit around the Sun. Its distance from the Sun is four times the
average distance of Earth from the Sun.The period of this planet, in Earth years, is :
A) 4
B) 8
C) 16
D) 32
E) 2
The Answer is B) 8.
I took this test, I know that for sure.
The term that describes the direction closest to the point of origin is Proximal. Dorsal is the directional term for the movement toward the back of the body. Cephalic is the term that describes the movement towards the top of the body. Ventral on the other hand describes the movement toward the front of the body.
Solution :
Given :
Weight = 4 lb
Stretched of a spring in equilibrium,Δ = 2 ft
a). We know that
F = kΔ
4 = k x 2
k = 2 lb/ft
∴ Stiffness of the spring is, k = 2 lb/ft
Motion is critically damped.
C = 0.99729 lb.s/ft.
b). Displacement
Initial displacement = 6 inches
Therefore, displacement :
<h3>
<u>Provided</u><u>:</u><u>-</u></h3>
- Initial velocity = 15 m/s
- Final velocity = 10 m/s
- Time taken = 2 s
<h3><u>To FinD:-</u></h3>
- Accleration of the particle....?
<h3>
<u>How</u><u> </u><u>to</u><u> </u><u>solve</u><u>?</u></h3>
We will solve the above Question by using equations of motion that are:-
- v = u + at
- s = ut + 1/2 at²
- v² = u² + 2as
Here,
- v = Final velocity
- u = Initial velocity
- a = acceleration
- t = time taken
- s = distance travelled
<h3>
<u>Work</u><u> </u><u>out</u><u>:</u></h3>
By using first equation of motion,
⇛ v = u + at
⇛ 10 = 15 + a(2)
⇛ -5 = 2a
Flipping it,
⇛ 2a = -5
⇛ a = -2.5 m/s² [ANSWER]
❍ Acclearation is negative because final velocity is less than Initial velocity.
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Answer:
Explanation:
According to Newton's second law, we have:
The force of friction is opposite to the motion of the block.
Using the following kinematic equation, we can calculate the distance traveled by the block before it stops().
Solving for x and replacing a from (1):