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FinnZ [79.3K]
3 years ago
12

What temperature does water freeze at in celsius and fahrenheit?

Physics
2 answers:
andre [41]3 years ago
4 0
32 degrees Fahrenheit
And
0 degrees Celsius
Illusion [34]3 years ago
4 0
- 0 degree celious water freezing
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A 6.0 m section of wire carries a current of 5.2 A from east to west in the earth's magnetic field of 1.0 × 105 T at a location
NNADVOKAT [17]
Well, since you only want direction, ignore the numbers. Use the right hand rule.
Current (pointer finger) points west (left). 
Magnetic field (middle finger) points south (towards you). 
Force (thumb) then points up (away from the earth)
4 0
3 years ago
An underground gasoline tank can hold 1.07 103 gallons of gasoline at 52.0°F. If the tank is being filled on a day when the outd
Damm [24]

Answer:

1069.38 gallons

Explanation:

Let V₀ = 1.07 × 10³ be the initial volume of the gasoline at temperature θ₁ = 52 °F. Let V₁ be the volume at θ₂ = 97 °F.

V₁ = V₀(1 + βΔθ)  β = coefficient of volume expansion for gasoline = 9.6 × 10⁻⁴ °C⁻¹

Δθ = (5/9)(97°F -52°F) °C = 25 °C.

Let V₂ be its final volume when it cools to 52°F in the tank is

V₂ = V₁(1 - βΔθ) = V₀(1 + βΔθ)(1 - βΔθ) = V₀(1 - [βΔθ]²)

    = 1.07 × 10³(1 - [9.6 × 10⁻⁴ °C⁻¹ × 25 °C]²)

    = 1.07 × 10³(1 - [0.024]²)

    =  1.07 × 10³(1 - 0.000576)

    = 1.07 × 10³(0.999424)

    = 1069.38 gallons

7 0
3 years ago
A piston releases 18 J of heat into its surroundings while expanding from 0.0002 m^3 to 0.0006 m^3 at a constant pressure of 1.0
Elodia [21]

Answer:

value of heat is 18 J

2. step by step

formular w=p(volume1-volume2)

w= 1.0×10^5(0.0006-0.0004)

w= 40 J

8 0
3 years ago
The​ half-life of a certain radioactive substance is 12 hours. There are 19 grams present initially. a. Express the amount of su
neonofarm [45]

Answer:

(a) N=19\times e^{-\lambda t}

(b) 15 hours

Explanation:

half life, T = 12 hours

No = 19 g

(a) Let N be the amount remaining after time t.

Let λ be the decay constant.

\lambda =\frac {0.6931}{T}

The equation of radioactivity used here is given by

N=N_{o}e^{-\lambda t}

N=19\times e^{-\lambda t}

(b) N = 8 gram

Substitute the values in above equation

\lambda =\frac {0.6931}{12}

λ = 0.0577 per hour

So, 8=19\times e^{-0.577t}

e^{-0.0577t}=0.421

Take natural log on both the sides

- 0.0577 t = - 0.865

t = 15 hours

4 0
3 years ago
A ball traveling at 15 m/s hits a bat with a force of 200N. How much force does the bat (moving at 20m/s)
just olya [345]

Answer:

200 N

Explanation:

Given that,

A ball traveling at 15 m/s hits a bat with a force of 200 N.

We need to find the force that the bat moving at 20 m/s hit the ball with.

We know that, this probelm is based on Newton's third law of motion. The force that the ball exerting on bat should be equal to the force that the bat exerting in the ball but in opposite direction.

It would mean that the ball hits the ball with a force of 200 N. Hence, the correct option is (a).

8 0
3 years ago
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