URGENT!!! How many molecules of water are produced when a molecule of C7H16 combusts

A student designs an experiment where he takes a small wood car with 1.0 inch diameter wheels and rolls it down a ramp. The stud

aleksley [76]

The metal car airodinamics with body style and weight increased speed

8 0

4 years ago

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Two litres of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 litres. How m

nlexa [21]

Answer:

The work done and heat absorbed are both -8,1 kJ

Explanation:

The work done in an isobaric process is defined as:

W = -P (Vf - Vi)

Where P is pressure ( 10 atm)

Vf = 10 L

Vi = 2 L

Thus, <em>W = -80 atm×L ≡ -8,1 kJ</em>

This is the work done in expansion of the gas. As the gas remains at the same temperature, there is no change in internal energy doing that all work was absorbed as heat.

I hope it helps!

4 0

3 years ago

How many grams of lithium sulfide must be dissolved in 1600.0 g water to make a 2.0 molal solution?

klasskru [66]

Molality is the number of moles of solutes in 1 kg of solvent.
the molality of solution to be prepared is 2.0 molal.
therefore 2 moles in 1 kg water.
the mass of Li₂S required is - 46 g/mol x 2.0 mol = 92 g
the mass in 1 kg of solvent is - 92 g
Therefore mass of Li₂S required in 1600.0 g is - 92 g/kg x 1.6 kg = 147.2 g

7 0

3 years ago

A bulldozer does 15,000 J of work lifting dirt 15 m up to get it out of a hole. How much force did the bulldozer use to accompli

nika2105 [10]

Answer:

<h3>The answer is 3000 N</h3>

Explanation:

The amount of force can be found by using the formula

$f = \frac{w}{d} \\$

w is the workdone

d is the distance

From the question we have

$f = \frac{15000}{5} \\$

We have the final answer as

Hope this helps you

7 0

3 years ago

How many grams of Na2So4 would be formed if 0.75 moles of NaOH reacted?

Nata [24]

Answer:

$\boxed{\text{53 g }}$

Explanation:

You don't give the reaction, but we can get by just by balancing atoms of Na.

We know we will need the partially balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.

M_r: 142.04

2NaOH + … ⟶ Na₂SO₄ + …

n/mol: 0.75

1. Use the molar ratio of Na₂SO₄ to NaOH to calculate the moles of NaF.

Moles of Na₂SO₄ = 0.75 mol NaOH × (1 mol Na₂SO₄/2 mol NaOH

= 0.375 mol Na₂SO₄

2. Use the molar mass of Na₂SO₄ to calculate the mass of Na₂SO₄.

Mass of Na₂SO₄ = 0.375 mol Na₂SO₄ × (142.04 g Na₂SO₄/1 mol Na₂SO₄) = 53 g Na₂SO₄

The reaction produces $\boxed{\text{53 g }}$ of Na₂SO₄.

4 0

3 years ago