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EastWind [94]
3 years ago
6

The solubility of kcl in ethanol is 0.25 g / 100 ml at 25 oc. how does this compare to the solubility of kcl in water?

Chemistry
1 answer:
babunello [35]3 years ago
6 0
The solubility is higher in water. 
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Why aren't flowers sold at a monastery math worksheet answers?
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1) x/9 + 16 = 5.

a) x/9 + 16 - 16 = 5 -16; subtraction.

b) x/9 = -11; simplifying.

c) x/9 · 9 = -11 · 9; multiplication.

d) x = -99; simplifying.

2) 5 · (2a - 3) = 60.

a) 10a - 15 = 60; distributive.

b) 10 - 15 + 15 = 60 + 15; addition.

c) 10a = 75; simplifying.

d) 10a ÷ 10 = 75 ÷ 10; commutative.

e) a = 7.5; simplifying.

3) 4 n + (7 + n) = 52.

a) 4n + (n + 7) = 52; commutative.

b) ( 4n + n) + 7 = 52; associative.

c) 5n + 7 = 52; combining.

d) 5n + 7 - 7 = 52 - 7; subtraction.

e) 5n = 45; simplifying.

f) 5n ÷ 5 = 45 ÷ 5; division.

g) n = 9; simplifying.

4) 8t - 3 · (4t + 2) = 16.

a) 8t - 12 t - 6 = 16; distributive.

b) -4 t - 6 = 16; combining.

c) - 4 t - 6 + 6 = 16 + 6; addition.

d) -4t = 22; simplifying.

e) -4t ÷ (-4) = 22 ÷ (-4); division.

f) t = -5.5; simplifying.

This is the question I found on internet.

8 0
3 years ago
Read 2 more answers
Arrange the following H atom electron transitions in order of increasing frequency of the photon absorbed or emitted:
Setler [38]

The order of frequency is d < a < c < b

E_{n} = 13.6 * z^{2} / n^{2} eV

where z = atomic mass number

n = energy level

For hydrogen z = 1

Therefore, Energy for n = 1

E_{n} = 13.6 * 1^{2} / 1^{2} eV

     = -13.6 eV

for n = 2

E_{n} = 13.6 * 1^{2} / 2^{2} eV

     = -3.40 eV

for n = 3

 E_{n} = 13.6 * 1^{2} / 3^{2} eV

      = -1.51 eV

for n = 4

 E_{n} = 13.6 * 1^{2} / 4^{2} eV

      = -0.85 eV

for n = 5

 E_{n} = 13.6 * 1^{2} / 5^{2} eV

      = -0.544 eV

n = 2 to n = 4 (absorption)

ΔE = E4 - E2   = -0.85 - (-3.40) = 2.55 eV

n = 2 to n = 1 (emission)

ΔE =  E1 - E2  = -13.6 - (-3.40) = -10.2eV

The negative sign indicates that emission will take place.

n = 2 to n = 5 (absorption)

ΔE = E5 - E2 = -0.544 - (-3.40) = 2.856 eV

n = 4 to n = 3 (emission)

ΔE = E3 - E4 = -1.51 - (-0.85) = -0.66 eV

We know that

E = h * υ

Therefore, Energy is proportional to frequency.

So increasing the order of energy is

E4  < E1  < E3  <  E2

order of frequency is

d < a < c < b

For more information click on the link below:

brainly.com/question/17058029

# SPJ4

8 0
1 year ago
Why isn't the atomic mass of most of the elements on the Periodic Table an integer (not a decimal)?
elena55 [62]

Answer:

Atomic mass is never an integer number for several reasons

4 0
3 years ago
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