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dedylja [7]
2 years ago
12

37. Which body exerts the strongest gravitational force on you?

Physics
2 answers:
antoniya [11.8K]2 years ago
8 0

The Sun is the body that exerts the strongest gravitational force on us.

The Sun exerts the strongest gravitational energy due its huge size and

mass . This also helps it to keep the other members of the solar system such

as the moon, planets and stars in a defined path and prevents them crashing into each other.

The Sun is a very important object in the solar system as a result of its large

size and mass and ability to release solar energy for food production in plants.

Read more on brainly.com/question/25356732

PolarNik [594]2 years ago
5 0

The gravitational force of sun is the strongest because sun has the largest mass and acceleration due to gravity of about 275 m/s².

According to Newton's second law of motion, the gravitational force exerted by each planet or object is directly proportional to acceleration due to gravity and the mass of the object or planet.

The magnitude of the gravitational force is calculated as;

F = mg

where;

  • <em>m is the mass of the object</em>
  • <em>g is the acceleration due to gravity</em>

Therefore, the gravitational force of sun is the strongest because sun has the largest mass and acceleration due to gravity of about 275 m/s².

Learn more here:brainly.com/question/17301500

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If you pick up and carry a piece of heavy furniture which type of friction do you have with the floor
Phoenix [80]
Sliding Friction hope its right
7 0
3 years ago
A motor keep a Ferris wheel (with moment of inertia 6.97 × 107 kg · m2 ) rotating at 8.5 rev/hr. When the motor is turned off, t
Talja [164]

Answer:

P = 133.13 Watt

Explanation:

Initial angular speed of the ferris wheel is given as

\omega_i = 2\pi f

\omega_i = 2\pi(8.5/3600)

\omega_i = 0.015 rad/s

final angular speed after friction is given as

\omega_f = 2\pi f

\omega_f = 2\pi(7.5/3600)

\omega_f = 0.013 rad/s

now angular acceleration is given as

\alpha = \frac{\omega_f - \omega_i}{\Delta t}

\alpha = \frac{0.015 - 0.013}{15}

\alpha = 1.27 \times 10^{-4} rad/s^2

now torque due to friction on the wheel is given as

\tau = I \alpha

\tau = (6.97 \times 10^7)(1.27 \times 10^{-4})

\tau = 8875.3 N m

Now the power required to rotate it with initial given speed is

P = \tau \omega

P = 8875.3 \times 0.015

P = 133.13 Watt

8 0
3 years ago
What is the acceleration of an 24 kg object that applies a force of 130N?
WITCHER [35]

Answer:

To find the acceleration of the object we have to apply Newton second law of motion that is F = mass × acceleration.

Explanation:

Given ,

F = 130N

M = 24kg

A = ?

F = m× a

then ,

130N = 24kg ×a

a = 130/24 = 5 m/s.

6 0
2 years ago
When dots are printed from a laser printer to form letters, they must be close enough so that you do not see the individual dots
balandron [24]

Answer: separate them

Explanation:

3 0
3 years ago
0.042 kg … ________________grams
olchik [2.2K]

Answer:

42 grams

Explanation:

you multiply the value by 1000 to get your answer

6 0
3 years ago
Read 2 more answers
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