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dedylja [7]
2 years ago
12

37. Which body exerts the strongest gravitational force on you?

Physics
2 answers:
antoniya [11.8K]2 years ago
8 0

The Sun is the body that exerts the strongest gravitational force on us.

The Sun exerts the strongest gravitational energy due its huge size and

mass . This also helps it to keep the other members of the solar system such

as the moon, planets and stars in a defined path and prevents them crashing into each other.

The Sun is a very important object in the solar system as a result of its large

size and mass and ability to release solar energy for food production in plants.

Read more on brainly.com/question/25356732

PolarNik [594]2 years ago
5 0

The gravitational force of sun is the strongest because sun has the largest mass and acceleration due to gravity of about 275 m/s².

According to Newton's second law of motion, the gravitational force exerted by each planet or object is directly proportional to acceleration due to gravity and the mass of the object or planet.

The magnitude of the gravitational force is calculated as;

F = mg

where;

  • <em>m is the mass of the object</em>
  • <em>g is the acceleration due to gravity</em>

Therefore, the gravitational force of sun is the strongest because sun has the largest mass and acceleration due to gravity of about 275 m/s².

Learn more here:brainly.com/question/17301500

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A wire is wrapped around a piece of iron, and then electricity is run through the wire. What happens to the iron?
katrin [286]
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7 0
3 years ago
Two friends, Al and Jo, have a combined mass of 195 kg. At the ice skating rink, they stand close together on skates, at rest an
ddd [48]

Answer:

Al's mass is 102.92  kg  

Explanation:

As there are no external forces in the horizontal direction, the horizontal net force must be zero:

F_{net} = 0

As the force is the derivative in time of the momentum, this means that the horizontal momentum is constant:

F_{net} = \frac{dp_{horizontal}}{dt} = 0

p_{horizontal_i }= p_{horizontal_f}

where the suffix i and f means initial and final respectively.

The initial momentum will be:

p_{horizontal_}i = m_{Al} \ v_{Al_i} + m_{Jo} \ v_{Jo_i}

But, as they are at rest, initially

p_{horizontal_i} = m_{Al} * 0 + m_{Jo} * 0

p_{horizontal_i} = 0

So, this means:

p_{horizontal_f} = m_{Al} \ v_{Al_f} + m_{Jo} \ v_{Jo_f} = 0

We know that the have an combined mass of 195 kg:

m_{total} = m_{Al} + m_{Jo} = 195 \ kg.

so:

m_{Jo} = 195 \ kg - m_{Al}.

m_{Al} \ v_{Al_f} + (195 \ kg - m_{Al}) \ v_{Jo_f} = 0

m_{Al} \  v_{Al_f} - m_{Al} \  v_{Jo_f}= - 195 \ kg \  v_{Jo_f}

m_{Al} \ (v_{Al_f} - v_{Jo_f})= - 195 \ kg \ v_{Jo_f}

m_{Al} = \frac{ - 195 \ kg \ v_{Jo_f} } {  v_{Al_f} - v_{Jo_f} }

m_{Al} = \frac{195 \ kg  \ v_{Jo_f} } {    v_{Jo_f} - v_{Al_f} }

Now, we can use the values:

v_{Al_f}= 10.2 \frac{m}{s}

v_{Jo_f}= - 11.4 \frac{m}{s}

where the minus sign appears as they are moving at opposite directions

m_{Al} = \frac{195 \ kg  ( - 11.4 \frac{m}{s} ) } {   (- 11.4 \frac{m}{s}) - 10.2 \frac{m}{s} }

m_{Al} = 102.92 \ kg

and this is the Al's mass.

5 0
3 years ago
Discuss the limitations of using the Doppler shift to determine an object's speed.
pantera1 [17]

Answer and Explanation:

Limitation of Doppler shift :

The Doppler impact is relevant when the speeds of the wellspring of sound and spectator are considerably less than the speed of sound. The movement of both the spectator and the source is along a similar straight line.When movement is not in straight line or velocity is not much less than speed of light then we can not use Doppler shift

This is the limitation of Doppler shift to determine the object distance

3 0
3 years ago
A jet fighter flying at 300 m/s (just below the speed of sound) makes a turn of radius 1.85 km. (a) what is its centripetal acce
777dan777 [17]
centripetal acceleration can be determined using the following equation;
a = v² / r
a= centripetal acceleration
v = velocity 
r = radius
substituting the values in the equation,
a = (300 m/s)*(300m/s) / (1.85 *1000) m
   = 48.64 ms-²
7 0
3 years ago
The velocity of a particle is described
Dmitry_Shevchenko [17]

Answer:

hope you like it

Explanation:

To find velocity, we take the derivative of the original position equation. To find acceleration, we take the derivative of the velocity function. To determine the direction of the particle at t = 1 t=1 t=1, we plug 1 into the velocity function.

4 0
3 years ago
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