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2 years ago

37. Which body exerts the strongest gravitational force on you?

Physics

2 answers:

antoniya [11.8K]2 years ago

8 0

The Sun is the body that exerts the strongest gravitational force on us.

The Sun exerts the strongest gravitational energy due its huge size and

mass . This also helps it to keep the other members of the solar system such

as the moon, planets and stars in a defined path and prevents them crashing into each other.

The Sun is a very important object in the solar system as a result of its large

size and mass and ability to release solar energy for food production in plants.

Read more on brainly.com/question/25356732

PolarNik [594]2 years ago

5 0

The gravitational force of sun is the strongest because sun has the largest mass and acceleration due to gravity of about 275 m/s².

According to Newton's second law of motion, the gravitational force exerted by each planet or object is directly proportional to acceleration due to gravity and the mass of the object or planet.

The magnitude of the gravitational force is calculated as;

F = mg

where;

m is the mass of the object
g is the acceleration due to gravity

Therefore, the gravitational force of sun is the strongest because sun has the largest mass and acceleration due to gravity of about 275 m/s².

Learn more here:brainly.com/question/17301500

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Alona [7]

D. The measure of average kinetic energy of molecules of a substance

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3 years ago

A 40-cm-long tube has a 40-cm-long insert that can be pulled in and out. A vibrating tuning fork is held next to the tube. As th

Umnica [9.8K]

Answer:

The frequency of the tuning is 1.065 kHz

Explanation:

Given that,

Length of tube = 40 cm

We need to calculate the difference between each of the lengths

Using formula for length

$\Delta L=L_{2}-L_{1}$

$\Delta L=74.7-58.6$

$\Delta L=16.1\ m$

For an open-open tube,

We need to calculate the fundamental wavelength

Using formula of wavelength

$\lambda=2\Delta L$

Put the value into the formula

$\lambda=2\times16.1$

$\lambda=32.2\ cm$

We need to calculate the frequency of the tuning

Using formula of frequency

$f=\dfrac{v}{\lambda}$

Put the value into the formula

$f=\dfrac{343}{32.2\times10^{-2}}$

$f=1065.2\ Hz$

$f=1.065\ kHz$

Hence, The frequency of the tuning is 1.065 kHz

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A crate rests on a flatbed truck which is initially traveling at 17.9 m/s on a level road. The driver applies the brakes and the

Mamont248 [21]

Answer:

The minimum coefficient of friction required is 0.35.

Explanation:

The minimum coefficient of friction required to keep the crate from sliding can be found as follows:

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