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alexandr402 [8]
3 years ago
14

Different forces were applied to five balls, and each force was applied for the same amount of time. The data is in the table.

Physics
2 answers:
emmainna [20.7K]3 years ago
6 0
C. It doubles I hope this helps and good luck
Alja [10]3 years ago
6 0

The impulse provided to the ball is equal to the change in momentum of the ball.

According to Newton's second law, The rate of change of momentum is directly proportional to the force applied. Hence, the equation can be written as:

Δp = F × t

Δp = change in momentum = Impulse

F = Force

t = time for which the force is applied

Now. if the force is doubled and the time remains same.

F(new) = 2F

t = t

Δp (new) = 2F × t

Δp (new) = 2 Δp (old)

Hence, the impulse gets doubled

Option C is correct.

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Answer:

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Explanation:

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Newton’s law of universal gravitation states that the force of gravity
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Which term is defined by the force that moving, charged particles exert on one another?
Lisa [10]

Answer:

Electromagnetic force

Explanation:

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- Electromagnetic force: it is the force exerted between charged objects and between magnets (it is responsible for electric fields and magnetic fields). It is the 2nd strongest force, and it is the force that holds atoms in a molecule together. It can be attractive or repulsive, and it has an infinite range.

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Why Study Science? Help me out
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) A stone initially moving at 8.0 m/s on a level surface comes to rest due to friction after it travels 11 m. What is the coeffi
natali 33 [55]

Answer:

-0.3

Explanation:

F' = μmg ........... Equation 1

Where F' = Frictional force, μ = coefficient of kinetic friction, m = mass of the stone, g = acceleration due to gravity.

But,

F' = ma ............ Equation 2

Where a = acceleration of the stone.

Substitute equation 2 into equation 1

ma = μmg

dividing both side of the equation by m

a = μg

make μ the subject of the equation

μ = a/g............... Equation 3

From the equation of motion,

v² = u²+2as................. Equation 4

Where v and u are the final and the initial velocity respectively, s = distance.

Given: v = 0 m/s (to rest), u = 8.0 m/s, s = 11 m.

Substitute into equation 4

0² = 8² + 2×11×a

22a = -64

a = -64/22

a = -32/11 m/s² = -2.91 m/s²

substitute the values of a and g into equation 3

μ = -2.91/9.8

μ = -0.297

μ ≈ -0.3

4 0
3 years ago
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