Answer:
Explanation:
fringe separation or fringe width is directly proportional to wavelength .
Δ₁ / Δ₂ = wave length of first laser / wavelength of second laser
Δ₁ is fringe separation in first case and Δ₂ is fringe separation in second case.
putting the given values
632.8 / wavelength of second laser = 4.5 / 4.64
wavelength of second laser = 632.8 x (4.64 / 4.5)
= 652.48 nm
652 nm
Answer:
everything is perished isn't it?
hope it helps.
Because the silt (dirt particles) in muddy water eventually settles out, the muddy water is a __suspension__ .
Answer:
0.44 V
Explanation:
Parameters given:
Radius of loop, r = 10.7 cm = 0.107 m
Magnetic field strength, B = 0.803 T
Rate of shrinkage of Radius, dr/dt = 81 cm/s = 0.81m/s
EMF induced is given in terms of magnetic Flux, Φ, as:
EMF = dΦ/dt
Magnetic Flux, Φ, is given as:
Φ = B * A (where A is area of loop)
Therefore, EMF is:
EMF = d(B*A)/dt
The area of the loop is given as A = πr²
EMF = d(Bπr²) / dt = Bπ*d(r²)/dt
=> EMF = Bπ*2r*(dr/dt)
EMF = 0.803 * π * 2 * 0.107 * 0.81
EMF = 0.44 V
Answer:
8.42Joules
Explanation:
The rotational kinetic energy, denoted by E(rotational), can be calculated using the formula:
E(rotational) = 1/2 × I × ω²
Where;
I = moment of inertia (kgm²)
ω = angular velocity (rad/s)
However, we need to calculate the moment of inertia in this question by using the formula:
I = m × r²
Where;
m = mass (1.3kg)
r = radius (0.6m)
I = 1.3 × 0.6²
I = 1.3 × 0.36
I = 0.468 kgm²
Since I = 0.468 kgm², ω = 6 rad/s, we can calculate rational kinetic energy using:
K.E(rotational) = 1/2 × I × ω²
K.E(rotational) = 1/2 × 0.468 × 6²
K.E(rotational) =1/2 × 0.468 × 36
K.E(rotational) = 18 × 0.468
K.E(rotational) = 8.424
K.E(rotational) = 8.42Joules
