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Elan Coil [88]
4 years ago
13

What unit can be used to measure length or distance

Physics
1 answer:
strojnjashka [21]4 years ago
7 0

Answer:

The most common units that we use to measure length in the metric system are the millimeter, centimeter, meter, and kilometer.

Explanation:

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What do measurements of the number of neutrinos emitted by the Sun tell us about conditions deep in the solar interior?
OverLord2011 [107]

Answer:

The neutrinos are produced in the core of the sun by nuclear fusion and measuring their number helps us confirm that there are enough proton-proton chain reactions of each which produce a neutrino and going on in the Sun's core to explain the energy output of the Sun.

4 0
3 years ago
What is the difference between a group and a period
Digiron [165]
Periods<span> going left to right. The periodic table also has a special name </span>for<span> its vertical columns. Each column </span>is<span> called a </span>group. The elements in eachgroup<span> have the same number </span>of<span> electrons </span>in the<span> outer orbital.</span>
5 0
3 years ago
The minimum breaking distance d in feet for a typical vehicle can be modeled with the equation d(v) = 0.045v2, where v is the ve
xxTIMURxx [149]
<span>To find the kind of transformation that describes this change from d(v) = 0.045v2 to d(v) = 0.039v2, find the relation between the two functions:

0.045/.039 = 45/39 = 15/13

The you have to multiply the first function times 13/15 to transform it to the second function.

When you multiply by a factor less than one you are compressiong the function vertically (if you multiply by a factor greater than 1 you are stretching vertically).

On the other hand, that the distance to stop the minimum braking distance will be smaller with the second function.

Then, the answer is that the transformation is a vertical compression by a factor of 13/15 and the braking distance will be less with optimum new tires than with tires having more wear.
</span>
3 0
4 years ago
A 21500 kg jet airplane is flying through some high winds. At some point in time, the airplane is pointing due north, while the
GalinKa [24]

Answer:\theta =79.47 North\ of\ west

Explanation:

Given

Mass of airplane =21500 kg

Force due to jet engines=35100 N

Force from wind is 14900 N at angle of 75 south of west

Resolving forces

F_x=14900cos75=-3856.403 N

F_y=35100-14900sin75

F_y=35100-14392.29=20707.70 N

Therefore acceleration in x direction

a_x=\frac{F_x}{m}=\frac{-3856.403}{21500}=-0.179 m/s^2

a_y=\frac{F_y}{m}=\frac{20707.70}{21500}=0.963 m/s^2

Direction of acceleration

tan\theta =\frac{a_y}{a_x}=\frac{0.963}{0.179}=-5.38

\theta =79.47\ North\ of\ west

5 0
4 years ago
A force of 62 N acts on a 35 kg object for 10.0s. What is the objects change in momentum?
Makovka662 [10]

Answer:

Δp = 620 N.s

Explanation:

  • Newton's second law, was originally conceived  as follows:

       F = \frac{\Delta p}{\Delta t}  (1)

  • In this way, a net force applied on an object, is equal to the rate of change of the momentum of the object regarding time.

       for m= constant, it reduces to F= m*a.

  • Replacing in (1) F= 62 N, and Δt = 10.0 s, we can solve for Δp (object's change in momentum) , as follows:

       \Delta p = F* \Delta t = 62 N* 10.0 s = 620 N*s  (2)

7 0
3 years ago
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