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Oksanka [162]
3 years ago
12

What divided by 50.41 = 0.5041

Mathematics
2 answers:
VashaNatasha [74]3 years ago
5 0
X / 50.41 = 0.5041

x = 50.41 * 0.5041

x = 25.411681


beks73 [17]3 years ago
3 0
50.41 divided by 100 = 0.5041
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How do you factorise 8p-12
Murrr4er [49]

factor by finding a common number you can divide both by


8p-12 and both can be divided by highest number of 4

4(2p-3)  that's it

5 0
3 years ago
Just this one
S_A_V [24]

Answer:

15%

Step-by-step explanation:

900/6000

which is the same as 900÷6000

900÷6000= 0.15

0.15 as a percent in 15%

7 0
2 years ago
What is the value of g(−3) when g(x)=2x−2 ?
nikdorinn [45]
For these types of problems, plug the value inside the ( ) into the (x) of the equation.
g (-3), g (x) = 2x-2
g (x) = 2 (-3) - 2 = -6 - 2 = -8
g (-3) = -8
3 0
3 years ago
Read 2 more answers
5 watermelons 6 cantaloupes cost $54. 4 watermelons and 8 cantaloupes $56. how much is a cantaloupe
GREYUIT [131]

Answer:

A cantaloupe costs $4

Step-by-step explanation:

Watermelons = W

Cantaloupes = C

Write given statements as equations

5W + 6C = 54

4W + 8C = 56

Simplify the second equation

4W + 8C = 56

Subtract 8C from both sides of the equation

4W = 56 - 8C

Divide both sides of the equation by 4

W = 14 - 2C

Substitute into second equation

5W + 6C = 54

5(14 - 2C) + 6C = 54

Multiply 5(14 - 2C)

70 - 10C + 6C = 54

Add -10C + 6C

70 - 4C = 54

Add 4C to both sides of the equation

70 = 54 + 4C

Subtract 54 from both sides of the equation

16 = 4C

Divide both sides of the equation by 4

C = 4

A cantaloupe costs $4

5W + 6(4) = 54

Multiply 6(4)

5W + 24 = 54

Subtract 24 from both sides of the equation

5W = 30

Divide both sides of the equation by 5

W = 6

A cantaloupe costs $4

A watermelon costs $6

Hope this helps :)

8 0
3 years ago
2. The ratio of radii of two cylinders is 1:2 and heights are in the ratio 2:3. Find the ratio of their volumes.
Savatey [412]

Answer: \frac{1}{6} or 1:6

Step-by-step explanation:

The volume of a cylinder can be found with the following formula:

V=\pi r^2h

Where "r" is the radius and "h" is the height of the cylinder.

In this case, let be:

- V_1 the volume of one of this cylinders and V_2 the volume of the other one.

- r_1 the radius of the first one and r_2 the radius of the other cylinder.

- h_1 the height of one of them and h_2 the height of the other cylinder.

Then:

V_1=\pi r_1^2h_1\\\\V_2=\pi r_2^2h_2

Therefore, you know this:

\frac{V_1}{V_2} =\frac{\pi r_1^2h_1}{\pi r_2^2h_2}

Simplifying, you get:

\frac{V_1}{V_2} =\frac{ r_1^2h_1}{ r_2^2h_2}

Now, knowing the ratios given in the exercise, you can substitute them into the equation:

\frac{V_1}{V_2} =\frac{1^2*2}{ 2^2*3}

Evaluating, you get:

\frac{V_1}{V_2} =\frac{2}{ 4*3}\\\\\frac{V_1}{V_2} =\frac{2}{12}\\\\\frac{V_1}{V_2} =\frac{1}{6}

4 0
3 years ago
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