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2 years ago

You are given a model of various phases of the moon, as shown below. You can tell right away that it is inaccurate.

Chemistry

2 answers:

erma4kov [3.2K]2 years ago

8 0

Explanation:

First of all, depending on the order of which the phases in this picture are sequenced, C and D should be flipped. the 3/4 moon appears before the full moon.

Second of all, A, which is what's supposed to be a waxing crescent moon, the illuminated side should be a bit larger than what is shown. the illuminated area should be about 1/4 of the whole area of the moon circle.

Hope this helps.

a_sh-v [17]2 years ago

3 0

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____ 30. isotopes are atoms of the same element that

finlep [7]

Isotopes are atoms of the same element that has different masses.

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3 years ago

Write the chemical formula for the anion present in the aqueous solution of cuso4.

ki77a [65]

SO4 -2, or Sulfate

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3 years ago

Read 2 more answers

0.10 M potassium chromate is slowly added to a solution containing 0.20 M AgNO3 and 0.20 M Ba(NO3)2. What is the Ag+ concentrati

erastova [34]

Answer:

$[Ag^{+}]=4.2\times 10^{-2}M$

Explanation:

Given:

[AgNO3] = 0.20 M

Ba(NO3)2 = 0.20 M

[K2CrO4] = 0.10 M

Ksp of Ag2CrO4 = 1.1 x 10^-12

Ksp of BaCrO4 = 1.1 x 10^-10

$BaCrO_4 (s)\leftrightharpoons Ba^{2+}(aq)\;+\;CrO_{4}^{2-}(aq)$

$Ksp=[Ba^{2+}][CrO_{4}^{2-}]$

$1.2\times 10^{-10}=(0.20)[CrO_{4}^{2-}]$

$[CrO_{4}^{2-}]=\frac{1.2\times 10^{-10}}{(0.20)}= 6.0\times 10^{-10}$

Now,

$Ag_{2}CrO_4(s) \leftrightharpoons 2Ag^{+}(aq)\;+\;CrO_{4}^{2-}(aq)$

$Ksp=[Ag^{+}]^{2}[CrO_{4}^{2-}]$

$1.1\times 10^{-12}=[Ag^{+}]^{2}](6.0\times 10^{-10})$

$[Ag^{+}]^{2}]=\frac{1.1\times 10^{-12}}{(6.0\times 10^{-10})}= 1.8\times 10^{-3}$

$[Ag^{+}]=\sqrt{1.8\times 10^{-3}}=4.2\times 10^{-2}M$

So, BaCrO4 will start precipitating when [Ag+] is 4.2 x 1.2^-2 M

7 0

3 years ago

Which is heavier einsteinium (Es) or europium (Eu)

SVETLANKA909090 [29]

I think the answer is einsteinium is the heavier one here.

8 0

3 years ago

According to the law of conservation of mass, what should the product side of this single replacement reaction look like? A. H2

Katyanochek1 [597]

Answer: The product side must be $ZnCl_2+H_2$

Explanation:

Single displacement reaction is defined as the reaction in which more reactive metal displaces a less reactive metal from its chemical reaction.

$AB+C\rightarrow CB+A$

Metal C is more reactive than metal A.

The reactivity of metal is determined by a series known as reactivity series. The metals lying above in the series are more reactive than the metals which lie below in the series.

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form. This also means that total number of individual atoms on reactant side must be equal to the total number of individual atoms on the product side.

When zinc metal reacts with hydrochloric acid, it leads to the production of zinc chloride and hydrogen gas. The chemical reaction follows:

$Zn+2HCl\rightarrow ZnCl_2+H_2$

On reactant side:

Number of zinc atoms = 1

Number of hydrogen atoms = 2

Number of chlorine atoms = 2

On product side:

Number of zinc atoms = 1

Number of hydrogen atoms = 2

Number of chlorine atoms = 2

Hence, the product side must be $ZnCl_2+H_2$

8 0

3 years ago