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ddd [48]
3 years ago
14

Solve for x: -16-6x = 6x(x+3)

Mathematics
1 answer:
jarptica [38.1K]3 years ago
5 0

Answer:

your answer is x=−2+ −2 3 √3 or x=−2+ 2 3 √3 my bro

Step-by-step explanation:

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What is the rest of the question?
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3 years ago
Chris can be paid in one of two ways. Plan A is a salary of $350 per month, plus a commission of 7% of a sales. pLan B is a sala
Lapatulllka [165]
Let's say, the total sales is "x"... .so hmm on Plan A, he gets 350 plus 7% of "x", well, 7% is just (7/100) * x or 0.07x

now, on Plan B, he gets 436 plus 5% of "x", 5% of "x" is (5/100) * x, or 0.05x

he's better off with A, only if A is greater than B, namely, A > B

\bf A\ \textgreater \ B\implies 350+0.07x\ \textgreater \ 436+0.05x
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0.07x-0.05x\ \textgreater \ 436-350\implies 0.02x\ \textgreater \ 86\implies x\ \textgreater \ \cfrac{86}{0.02}

and surely you know how much that is.
3 0
4 years ago
Suppose your friend's parents invest $15,000 in an account paying 5% compounded annually. What will the balance be after 6 years
Allisa [31]

Answer: i think it is $22,510.96 sorry if am wrong.

6 0
3 years ago
Label each statement as true or false regarding the zeros/roots of a quadratic function. The roots zeros of a quadratic function
ikadub [295]

Answer:

True, false, true, true.

Step-by-step explanation:

The roots zeros of a quadratic function are the same as the factors of the quadratic function. This is true because your roots are your factors—>(x-3) is a factor, x=3 is the root.

The roots zeros are the spots where the quadratic function intersects with the y-axis. No! Those are called y-intercepts!

The roots zeros are the spots where the quadratic function intersects with the x-axis. True. X-intercepts are your solutions. (x-3) graphed would the (3,0). That’s a solution.

There are not always two roots/zeros of a quadratic function,​ True. No solution would be when your quadratic doesn’t intersect the x-axis. One solution would be when your vertex would be on the x-axis. Two solutions is when your quadratic intersects the x-axis twice. Can there be infinite solutions? No. It’s either 0, 1, or 2 solutions.

6 0
3 years ago
Let L be the line with parametric equations x=2+t, y=1-t, z=1+3t.Let v=(1,2,0).Find vectors w1 and w2 such that v= w1 + w2, and
charle [14.2K]

Answer:

w1 = (-1/11, 1/11, -3/11)

w2 = (12/11, 21/11, 3/11)

Step-by-step explanation:

Direction ratio of w1 = Direction ratio of L (because parallel) = K+(1, -1, 3)

Let <a,b,c> be direction ratio of w2.

Then, <a,b,c>. <1,-1,3> = 0

a-b+3c = 0

v = w1 + w2

(1, 2, 0) = k(1, -1, 3) + (a, b, c)

a + k = 1

b - K = 2

c - 3k = 0

Solving 4 equations, a = 12/11, b= 21/11, c = 3/11, k=-1/11

So, w1 = -1/11(1, -1 ,3) = (-1/11, 1/11, -3/11)

w2 = (12/11, 21/11, 3/11)

6 0
3 years ago
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