You can solve this by putting the number of copies in the top part of the fraction. If you replace the one in the top part of 1/6 with 3, you get the fraction 3/6. Half of six is three and half of two is one, so both fractions are equal. You can test this be dividing the 3 in the top by 3 and the 6 in the bottom by three. Your result will be 1/2. Although there are three times ad many copies, each copy is three times as small, so it balances out.
Answer:
18 minutes
Step-by-step explanation:
Given that:
The arrival time = 3 customers / hour
The avg. service rate (s) = 12 minutes per customer
To hour, we have:
s = 5 customers/ hour
Thus, the required average time for a customer needs to wait in line is:
To minutes;
= 18 minutes
Answer:
1) 70 for both of them
2) Plot A's range is 100-50 = 50, Plot B's range is 100 - 40 = 60 so Plot A has the lesser range
3) Plot B's IQR is 85 - 60 = 25, Plot A's IQR is 80 - 65 = 15 so Plot B has the greater IQR
4) A: 80, B: 85
5) A: 65, B: 60
6) 50
7) 100
8) Plot B, see #2 for work
9) 50% - 50% of data is always between Q1 and Q3
10) 25%
11) 25%
Answer is in the attachment below. If you have any questions about the workings, just leave a comment below.
Answer:
a= k/4+9b
Step-by-step explanation:
hope this helps, if not let me know!
