50 grams salt
Volume of 50 Grams of Salt
50 Grams of Salt =
2.78 Tablespoons
8.33 Teaspoons
0.17 U.S. Cups
0.14 Imperial Cups
Data Given:
Initial Volume = V₁ = 36.7 L
Initial Pressure = P₁ = 145 kPa
Initial Temperature = T₁ = 65 °C + 273 = 338 K
Final Volume = V₂ = ?
Final Pressure = P₂ = 101.325 kPa (Standard Pressure)
Final Temperature = T₂ = 273 K (Standard Temperature)
Formula used:
As number of moles are constant, so Ideal Gas equation in following form is used,
P₁ V₁ / T₁ = P₂ V₂ / T₂
Solving for V₂,
V₂ = P₁ V₁ T₂ / T₁ P₂
Putting Values,
V₂ = (145 kPa × 36.7 L × 338 K) ÷ (273 K × 101.325 kPa)
V₂ = 1798667 ÷ 27661.25
V₂ = 65.02 L
The main properties of uranium-238 are as follows,
- The uranium-238 have orthorhombic crystal structure.
- The physical state of uranium-238 is solid.
- The uranium-238 have acid base properties.
- The uranium-238 have hard and silver white metal.
- The natural abundance of uranium-238 is 99%
The Atomic mass and atomic weight of uranium-238
- The atomic number of uranium-238 is 92
- The atomic weight of uranium-238 is 238.02
learn about uranium-238
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Answer:
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Answer:
0.2M
Explanation:
Data obtained from the question include:
C1 = 2.0 M
V1 = 100mL
V2 = 1000mL
C2 =?
Using the dilution formula C1V1 = C2V2, the molarity of the diluted solution can be obtained as follows:
C1V1 = C2V2
2 x 100 = C2 x 1000
Divide both side by the 1000
C2 = (2 x 100) / 1000
C2 = 0.2M
The molarity of the diluted solution is 0.2M
