Please list them from top to bottom, for exp like in your response, a,g,q,d. Giving quite some points for it.

Explain how skeletal muscles and nerves work together to help you move

Lana71 [14]

Sensors in the muscles and joints send messages back through peripheral nerves to tell the cerebellum and other parts of the brain where and how the arm or leg is moving and what position it's in

4 0

3 years ago

find the density, in g/cm3g/cm3 , of a metal cube with a mass of 50.3 gg and an edge length (l)(l) of 2.65 cmcm . for a cube v

Alina [70]

The density of the metal cube is 2.703 g/cm³.

The mass of a metal cube is m =50.3 grams.

The edge length of the metal cube is l = 2.65 cm.

Now, the density (ρ) of a cube can be given as:

ρ = m/(a)³

Where (a)³ is the volume of the cube, m is the mass of the cube, ρ is the density of the cube, and a is the length of one side of the cube.

Since the sides of a cube are equal therefore the value of a is the same for each edge length of the cube.

Now, the density of the metal cube in g/cm³ is:

ρ = m / a³

ρ = m / l³

ρ = 50.3 g / (2.65 cm)³

ρ = 50.3 g / (2.65 cm)(2.65 cm)(2.65 cm)

ρ = 50.3 g / 18.609 cm³

ρ = 2.703 g/cm³

Learn more about density here:

brainly.com/question/1354972

#SPJ4

4 0

2 years ago

What magnitude charge creates a 32.08 N/C electric field at a point 2.84 m away?

sammy [17]

Answer:

Q = 29.4 x 10⁻⁹ C.

Explanation:

Electric field due to a charge Q at distance d is given by coulomb law as follows

Electric field

E = k Q /d²

where for air k which is a constant is 9 x 10⁹

$E=\frac{k\times Q}{d^2}$

Given E = 32.08 , d = 2.84 m

Putting these values in the relation above, we have

$[tex]32.08=\frac{9\times 10^9\times Q}{(2.84)^2}$ [/tex]

Q = 29.4 x 10⁻⁹ C.

5 0

3 years ago

A block of cheese is sliding up an inclined surface that is not smooth.

labwork [276]

Answer:

I cant fit the entire picture but this should help

5 0

3 years ago

Read 2 more answers

(a) How fast must a 3000-kg elephant move to have the same kinetic energy as a 65.0-kg sprinter running at 10.0 m/ s?

Aleksandr-060686 [28]

Answer:

1.4719 m per sec

Explanation:

Hello

Kinetic energy is the energy associated with the movement of objects. Although there are many forms of kinetic energy

the formula to use is

$E=\frac{mv^{2} }{2}$

where m is the mass of the object and v the velocity

lets see the kinetic energy of the sprinter running

$E=\frac{65 Kg*10(\frac{m}{s} ^)){2} }{2} \\\\E=\frac{65 *100 }{2} \\E=3250 Joules\\\\$

Now, the elephant must have the same kinetic energy

$E=\frac{m*v_{2} ^{2} }{2} \\\\E*2=m*v_{2} ^{2}\\ \frac{2E}{m} =v_{2} ^{2} \\\sqrt{\frac{2E}{m} } =v_{2} \\\\\\v_{2} =\sqrt{\frac{2*3250}{3000} }\\ \\v_{2} =1.4719 \frac{m}{s} \\\\$

it works only the positive root, so the elephant must to walk to 1.4719 m/s to have the same kinetic energy.

Have a great day

8 0

3 years ago