The mass of carbon in 1 liter of mixture = 1.108 g
<h3>What is the mass of carbon in 1 liter of the mixture?</h3>
The mass of carbon in 1 liter of the mixture is determined as follows:
First the moles of gas is determined using the ideal gas formula:
n = (1 * 1)/(0.08205L * 298)
n = 0.0409 mole of total gas
mass of gas is then determined using the formula:
mass = 1 * 1.375
mass = 1.375 g
Let x = mass of CH₄ and y = mass of C₄H₁₀
x + y = 1.375 g
nCH₄ + nC₄H₁₀ = ntotat
moles = mass/molar mass
x + y = 1.695 => y = 1.695 - x
(x/molar mass of CH₄) + [(1.375 - x)/ molar mass C₄H₁₀ = 0.0409
x/16 + (1.375 - x)/58 = 0.0409
x = 0.380 g CH₄
y = 1.375 - 0.380
y = 0.995 g of C₄H₁₀
mass of C in CH₄ = 12/16 * 0.380 = 0.285
mass of C in C₄H₁₀ = 48/58 * 0.995 = 0.823
Mass of carbon in 1 liter of mixture = 0.285 + 0.823
Mass of carbon in 1 liter of mixture = 1.108 g
In conclusion, the carbon is the major component in the mixture.
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B.
I hope this will help a bit (Forgive me of its wrong pls)
The question is incomplete, the complete question is;
An unknown compound has the following chemical formula:
N2Ox
where x stands for a whole number.
Measurements also show that a certain sample of the unknown compound contains 3.7 mol of oxygen and 2.45 mol of nitrogen.
Write the complete chemical formula for the unknown compound.
Answer:
The complete formula of the compound is N2O3.
Explanation:
Given;
Number of moles of N = 2.45 moles
Number of moles of O = 3.7 moles
Chemical formula of unknown compound = N2Ox
From the ratio of the number of moles of N to O;
2/x = 2.45/3.7
2 * 3.7 = x * 2.45
x = 2 * 3.7/ 2.45
x =3
Hence the complete formula of the compound is N2O3.
Answer: Option (b) is the correct answer.
Explanation:
Chemical properties are defined as the properties which tend to chemical composition of a substance. Neutral elements with similar number of valence electrons tend to show similar chemical properties as these have same reactivity which actually affects their chemical properties.
This means that elements of the same group tend to show similar chemical properties.
For example, oxygen and sulfur atom are both group 16 elements and they have 6 valence electrons. Therefore, they show similar chemical properties.
Thus, we can conclude that a pair of O and S elements is expected to be most similar in their chemical properties.
