Answer:
Atomic mass
Explanation:
Atomic mass (Also called Atomic Weight, although this denomination is incorrect, since the mass is property of the body and the weight depends on the gravity) Mass of an atom corresponding to a certain chemical element). The uma (u) is usually used as a unit of measure. Where u.m.a are acronyms that mean "unit of atomic mass". This unit is also usually called Dalton (Da) in honor of the English chemist John Dalton.
It is equivalent to one twelfth of the mass of the nucleus of the most abundant isotope of carbon, carbon-12. It corresponds roughly to the mass of a proton (or a hydrogen atom). It is abbreviated as "uma", although it can also be found by its English acronym "amu" (Atomic Mass Unit). However, the recommended symbol is simply "u".
<u>
The atomic masses of the chemical elements are usually calculated with the weighted average of the masses of the different isotopes</u> of each element taking into account the relative abundance of each of them, which explains the non-correspondence between the atomic mass in umas, of an element, and the number of nucleons that harbors the nucleus of its most common isotope.
In contrast, the atomic mass of an isotope does coincide approximately with the mass of its nucleons. This difference is due to the fact that the elements are not formed by a single isotope but by a mixture with certain abundances for each of them. While when we measure the mass of a particular isotope, we do not take abundance into account. In any case, not even the atomic mass of the isotopes equals the sum of the masses of the nucleons. This is due to mass defect.
Evaporation is one change.
Answer:
2-methyl-2-butanol and 2-ethoxy-2-methylbutane
Explanation:
When the elimination occurs, a good leaving group must leave the compound and will be replaced. A good leaving group is a nucleophile, which intends to bond with compounds with positive charges. In this case, the bromine and iodine ions are nucleophiles that will leave the compounds.
In the mixture ethanol and water, two compounds must replace the leaving groups, which are strong nucleophiles: OH⁻ and ⁻OCH₂CH₃ (O is a strong nucleophile, and after the bonding, H⁺ will be lost in the ethanol molecule).
So, the two possible products are 2-methyl-2-butanol and 2-ethoxy-2-methylbutane, as shown below.
Answer:
The answer is
<h2>2.64 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 611 g
volume = final volume of water - initial volume of water
volume = 256.7 - 25.1 = 231.6 mL
The density of the metal is
We have the final answer as
<h3>2.64 g/mL</h3>
Hope this helps you