a. AgBr(s)⇒ Ag⁺(aq) + Br⁻(aq)
b. Ksp AgBr = s²
c. 5 x 10⁻¹³ mol/L
<h3>Further explanation</h3>
Given
solubility AgBr = 7.07 x 10⁻⁷ mol/L
Required
The dissolution reaction
Ksp
The solubility product constant
Solution
a. dissolution reaction of AgBr
AgBr(s)⇒ Ag⁺(aq) + Br⁻(aq)
b. Ksp
Ksp AgBr = [Ag⁺] [Br⁻]
Ksp AgBr = (s) (s)
Ksp AgBr = s²
c. Ksp AgBr = (7.07 x 10⁻⁷)² = 5 x 10⁻¹³ mol/L
Answer:
Alpha helixes:
- form long thin structures important for transmembrane proteins
- have a rigid spring like structure around a central axis
Beta sheets:
- Keep their shape due to hydrogen bonds between adjacent polypeptides chains
- have a flat zig zag like structure
Explanation:
Alpha helices and beta pleated sheets are two types of secondary structure found in proteins.
Alpha helix: In this structure, the polypeptide backbone is tightly wound around an imaginary central axis drawn longitudinally through the center with the R groups of the amino acids protruding outward from the helical backbone. This structure looks like a spring and could either be a left-handed or right-handed helix, though the left-handed helix has not been observed in proteins. Each turn of the helix includes about 3.6 amino acid residues.
The alpha helix is stabilized by a hydrogen bond between the hydrogen atom attached to the electronegative nitrogen atom of a peptide linkage and the electronegative carbonyl oxygen atom of the fourth amino acid on the amino-terminal side of that peptide bond.
Alpha-helices due to their structure, are the most common transmembrane proteins- protein structure element that crosses biological membranes.
Beta sheets: In the beta conformation, the backbone of the polypeptide chain is extended into a zigzag structure. The zigzag polypeptide chain can be arranged side by side to form a structure resembling a series of pleats known as beta sheets. Hydrogen bonds formed between adjacent segments of the polypeptide chain functions to stabilize the structure.
The beta comformation in the form of turns is common in globular proteins.
The impact that the oil spill has is environmental impacts.
Answer:
4NH₃ + 5O₂ → 4NO + 6H₂O ΔH = -904 kj
Explanation:
Given data:
Energy evolved when one mole of NH₃ react = 226 kj
Energy evolved when 4 mole of NH₃ react = ?
Solution:
Chemical equation:
4NH₃ + 5O₂ → 4NO + 6H₂O
It is stated in question that when one mole of ammonia react 226 kj energy evolved.
When 4 moles react energy evolved is,
1 mol = -226 kj
4 mol × -226 kj / 1mol
-904 kj
when 4 moles of ammonia react 904 kj energy is evolved.
Complete thermal equation:
4NH₃ + 5O₂ → 4NO + 6H₂O ΔH = -904 kj
Answer:
CCl4
Explanation:
Let us look at the structure of CCl4 closely in order to really determine if it is the correct answer to the question or not.
While it is true that the electro negativity of carbon is 2.5 and that of chlorine is 3.0, hence an electro negativity difference of 0.5 exists between carbon and chlorine leading to the presence of four polar covalent bonds in the carbon tetrachloride molecule. We must also observe that the molecule, carbon tetrachloride, has a tetrahedral molecular geometry. This implies that the four dipoles in the molecule are symmetrical and cancel out each other hence the molecule is non polar. Being a non polar molecule, only London forces are expected to be present as an intermolecular force, hence the answer.