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natali 33 [55]
3 years ago
6

Assignment a decomposer food chain exploration. Need help

Chemistry
1 answer:
satela [25.4K]3 years ago
7 0
I just finished my assignment and this is what I got. Try to put these in your own words. (: Hope this helps.

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How many molecules of water of hydration surround each molecule of sodium carbonate decahydrate, Na2CO3•10H2O
Klio2033 [76]
10 Molecules Because the coefficient shows how many molecules are there <span />
3 0
3 years ago
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When barium hydroxide is mixed with ammonium chloride, a fall in temperature is observed why? plz explain in detail
Oksanka [162]

Answer:

Ammonium chloride has ammonium (NH4 +) part which is slightly acidic and Barium Hydroxide is a strong base.

You can see that an acid-base reaction will occur.

In this case :

Its highly endothermic reaction

Forms aqueous ammonia (mind that ammonia is highly water soluble gas so no effervesence) and Barium Chloride which is water soluble.

Ba(OH)2 +NH4Cl ——->BaCl2 + NH3 +H2O (unbalanced)

4 0
3 years ago
How many calories are required to boil 75 grams of water not in sig figs
Norma-Jean [14]

Well, each ml of water requires one calorie to go up 1 degree Celsius, so this liter of water takes 1000 calories to go up 1 degree Celsius. (There are 1000 ml, each of which needs to have its temperature raised.)

3 0
2 years ago
The number of protons in a neutral atom is balanced by an equal number of
anastassius [24]
There would be an equal amounts of ELECTRONS.

In order for the atom to be neutral it would imply that the number of protons (positive particles) and the number of electrons (negative particles) are equal since the neutrons are without charge.
3 0
3 years ago
What is the pH of 1.00 L of a buffer that is 0.110 M nitrous acid (HNO2) and 0.200 M NaNO2? (pKa of HNO2 = 3.40)
Andrei [34K]

Answer:

pH = 3.65    

Explanation:

given data

pKa of HNO2 = 3.40

nitrous acid (HNO2) = 0.110 M

NaNO2 = 0.200 M

to find out

What is the pH

solution

we get here ph for acidic buffer  that is express as

pH = pKa + log(salt÷acid)      ........................1

put here value and we get

pH = 3.40 + log(0.200÷0.110)

pH = 3.65    

4 0
3 years ago
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