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3 years ago

What do you think could happen with methane gas and CO 2

Chemistry

1 answer:

Molodets [167]3 years ago

5 0

Answer:

these gases accumulate in the atmosphere and create the heat-reflective layer that keeps the Earth at a livable temperature. These gases form the insulation that keeps the planet warm enough to support life

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3. When 10.0 g of a pure compound was analyzed, it was found to contain 3.65 g of K, 3.33 g of CI,

vampirchik [111]

Convert all the grams to moles first.

K - 3.65 g / 39.1 g/mol = 0.0934 mol
Cl - 3.33 g / 35.45 g/mol = 0.0939 mol
O - 3.02 g / 16 g/mol = 0.189 mol

Divide them all by the smallest number of moles (0.0934 moles of K) to get whole numbers.

K - 0.0934/0.0934 = 1
Cl - 0.0939/0.0934 ≈ 1
O - 0.189/0.0934 ≈ 2

KClO2

5 0

3 years ago

The density of solid Ag is 10.5 g/cm3. How many atoms are present per cubic centimeter of Ag?

Sveta_85 [38]

Answer:

Unit cells which are present per cubic centimeter of Ag = $=1.45\times 10^{22}\ unit\ cells /cm^3$

Volume = $68.9\times 10^{-24}\ cm^3$

Edge length = $4.1\times 10^{-8}\ cm$

Explanation:

(a)

Given that:-

The density of the solid Ag = 10.5 g/cm³

Molar mass of silver = 107.8682 g/mol

So, Moles present per cm³ of Ag = $\frac{10.5\ g/cm^3}{107.8682\ g/mol}$ =0.0973 mol/cm³

Also, 1 mole = $6.023\times 10^{23}$ atoms.

So,

Atoms present per cm³ of Ag = $0.0973\ mol/cm^3\times 6.023\times 10^{23}\ atoms/mol=5.8\times 10^{22}\ atoms/cm^3$

Thus, answer = $5.8\times 10^{22}\ atoms/cm^3$

In FCC, the number of atoms in the unit cell = 4 unit cells

So,

Unit cells which are present per cubic centimeter of Ag = $\frac{5.8\times 10^{22}\ atoms/cm^3}{4}=1.45\times 10^{22}\ unit\ cells /cm^3$

Unit cells which are present per cubic centimeter of Ag = $=1.45\times 10^{22}\ unit\ cells /cm^3$

(b)

The reciprocal of the unit cell/cm³ is the volume of the unit cell.

So, $Volume=\frac{1}{1.45\times 10^{22}\ unit\ cells /cm^3}=68.9\times 10^{-24}\ cm^3$

Volume = $68.9\times 10^{-24}\ cm^3$

(c)

Also, Volume = ${(Edge\ length)}^3$

Thus, edge length = ${Volume}^{\frac{1}{3}}$ = $\left(68.9\times \:\:10^{-24}\right)^{\frac{1}{3}}\ cm=4.1\times 10^{-8}\ cm$

Edge length = $4.1\times 10^{-8}\ cm$

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4 years ago

Whoever awser right I will give you Brainly

pishuonlain [190]

Answer:

Explanation:

6 0

3 years ago

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The order of a reaction Z1) is the product of the powers to which the reactant concentrations are raised in the rate law. Z2) ca

irinina [24]

Explanation:

The Order of Reaction refers to the power dependence of the rate on the concentration of each reactant.

The overall order of reaction is the sum of the individual orders of reaction with respect to the reactants.

Rate = k [A]²[B]¹

In the rate law above, the rate is second order with respect to A and first order with respect to B. The overall order of reaction is a third order reaaction given as; 2+ 1 = 3

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4 years ago

Which of the following elements has the highest electronegativity?

zvonat [6]

The answer of this question is Oxygen

8 0

3 years ago

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