Rich says that light is the same thing as electromagnetic radiation. Do you agree or

Physics

1 answer:

guajiro [1.7K]3 years ago

5 0

Answer:

Yes, I agree with rich

Explanation:

Yes I agree with rich.

Thus is because;

The electromagnetic process is what will determine how electromagnetic radiation will be emitted. Now, the mode of travel of electromagnetic energy is in the form of waves and then the wavelength of these waves is what will enable us know the form of energy. This includes light, x-rays, gamma rays e.t.c. This means that light and the others are just parts of the spectrum emitted and are called photons.

Thus, light can be said to be electromagnetic radiation.

You might be interested in

A ball is dropped from a building of height h. Derive an equation for its velocity just before it hits the ground. Assume no air

swat32

Answer:

The final velocity of the ball just hits the ground is $\sqrt{2gh}$ .

Explanation:

A ball is dropped from the height h. As the ball is dropped means there is no initial velocity given to the ball.

GIVEN:

The distance traveled by the ball is equal to h.

Initial velocity of the ball is zero.

Concept:

Two type of force comes into play in dropping of ball.

1. Gravitational force

Due to gravitational force ball forced to fall downward towards the surface.

2. Air resistance

Air develops drag force on the ball in opposite direction of the gravitational force.

Assumption:

There is no air resistance in falling of ball. So, there will be no drag force on the ball.

Calculation:

It is given that a ball is dropped from a building of height h.

The Newton’s equations of motion are as follows:

$V^{2}-u^{2}=2as$

$s=ut+\frac{1}{2}at^{2}$

$v=u+at$

STEP 1

Newton’s equation of motion is expressed as follows:

$V^{2}-u^{2}=2as$

Here, V is final velocity of the ball just before the ball hits the ground, a is acceleration due to gravity, u is the initial velocity of the ball and s is the distance traveled by the ball.

Here, initial velocity is zero. So, u = 0 m/s.

Vertical distance traveled by the ball is h. So, s= h.

Only gravitational force is responsible for motion as well as for acceleration. Thus, the acceleration due to gravity acts on the ball. Acceleration due to gravity is denoted by small g.

Acceleration due to gravity is constant for different planate. The acceleration due to gravity for the earth is 9.8 m/s². Here, no planet is defined. So the acceleration due to gravity is a = g.

Substitute 0 for m/s, g for a and h for s in above equation as follows:

$V^{2}-u^{2}=2as$

$V^{2}-(0)^{2}=2gh$