Answer: The answer is option B
Explanation:
The base of the pyramid represents primary producers since they help to pass on energy to consumers as we go higher in the pyramid. They are not consumers because they supply energy and do not use up energy. They are called autotrophs.
One of the fundamental pillars to solve this problem is the use of thermodynamic tables to be able to find the values of the specific volume of saturated liquid and evaporation. We will be guided by the table B.7.1 'Saturated Methane' from which we will obtain the properties of this gas at the given temperature. Later considering the isobaric process we will calculate with that volume the properties in state two. Finally we will calculate the times through the differences of the temperatures and reasons of change of heat.
Table B.7.1: Saturated Methane




Calculate the specific volume of the methane at state 1



Assume the tank is rigid, specific volume remains constant


Now from the same table we can obtain the properties,
At 


We can calculate the time taken for the methane to become a single phase

Here
Initial temperature of Methane
Warming rate
Replacing



Therefore the time taken for the methane to become a single phase is 5hr
It is the red line the purple line carries the most the green line is the largest and the smallest is sky blue
Answer:
yes
Explanation:
because when you shot the ball your applying force to it
Answer:
v = ((m + M) / m)*√(2*g*h)
Explanation:
Given
m = mass of the projectile
M = mass of the ballistic pendulum
v = initial speed of the projectile
v' = speedof the system (pendulum + projectile) after the inelastic collision
h = maximum height reached for the system
Knowing that is an inelastic collision we have
m*v + M*(0) = (m+M)*v'
⇒ v' = m*v / (m+M)
After the collision, we apply the Principle of the Conservation of Energy
Ki + Ui = Kf + Uf
where
Ui = Kf = 0 J
then
Ki = Uf
0.5*(m+M)*v'² = (m+M)*g*h
⇒ 0.5*v'² = g*h
⇒ v'² = 2*g*h
⇒ (m*v / (m+M))² = 2*g*h
⇒ v = ((m+M) / m)*√(2*g*h)