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3 years ago

Chemical equation below demonstrate that? NEED HELP ASAP

Chemistry

1 answer:

zmey [24]3 years ago

7 0

(a) Matter cannot be created and destroyed by a chemical reaction.

Explanation:

(a) Matter cannot be created and destroyed by a chemical reaction. (correct)

The number and type of atoms entering the chemical reaction are the same with the number and type of atoms leaving the chemical reaction.

(b) The reactants are the same substance as the products. (wrong)

You may see in the reaction that we have as reactants zinc and hydrochloric acid which react to form the products, zinc chloride and hydrogen.

As reactants we have 2 hydrochloric acid (HCl) molecules and as products 1 hydrogen (H₂) molecule. Zn is a metal and ZnCl is a salt.

(d) The atoms on the reactants side are changed into different atoms on the products side. (wrong)

The number and type of atoms entering the chemical reaction are the same with the number and type of atoms leaving the chemical reaction.

Learn more about:

balancing chemical equations

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Blank and blank are examples of solids

Ymorist [56]

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3 years ago

Out of 500 silicon atoms: 460 are si-28, which has a mass of 27.98 amu 25 are si-29, which has a mass of 28.98 amu and 15 are si

liberstina [14]

Answer;

=28.09 amu

Explanation;

In this problem, they did not give us the percentages. However, since we know the number of atoms, we can easily calculate the percentages. For example:

(460 X 100)/500 = 92%

If we do this for all three isotopes,

(460 × 25)/500 = 5 %

(460 × 15) /500 = 3%

-We get 92%, 5%, and 3%. (We'll assume these are absolute numbers for determining our significant figures).

Now the problem is just like the previous one. First convert the percentages into decimals. Then multiply those decimals by the masses and add. Here's the solution:

= (0.92) X (27.98 amu) + (0.05) X (28.98 amu) + (0.03) X (29.97 amu)

= 25.74 amu + 1.449 amu + 0.8991 amu

= 28.09 amu

6 0

3 years ago

Read 2 more answers

Determine the empirical formula of a compound containing 40. 6 grams of carbon, 5. 1 grams of hydrogen, and 54. 2 grams of oxyge

zavuch27 [327]

The empirical formula is C₂H₃O₂

<h3>What is Empirical formula of a compound ?</h3>

The empirical formula is the simplest whole number ratio of elements present in a compound.

The total molar mass of the compound is 118.084 g/mol.

mass of Carbon present = 40.6

mass of Hydrogen present = 5.1 grams

mass of Oxygen present = 2 grams

Moles of C = 40.6/12 = 3.38

Moles of H = 5.1/1.008 = 5

Moles of Oxygen = 54.2/15.999 = 3.38

Ratio of Moles of C to Oxygen is 1 : 1

Ratio of Moles of C to H is 1/1.5

Multiplying each mole fraction by 2

The empirical formula is C₂H₃O₂

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