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3 years ago

What color will a star be with a surface temperature of 5000 6000 K?

Physics

2 answers:

11Alexandr11 [23.1K]3 years ago

6 0

The color of a star would with that surface temperature would be White. Hope this helps. :)

____ [38]3 years ago

6 0

Answer:

The color of a star be with a surface temperature of 5000 6000 K is Yellow.

C is correct option.

Explanation:

According to Wien's displacement law,

The black body radiation will peak at different wavelength due to different temperature.

In mathematical form,

$\lambda=\dfrac{2.89\times10^{-3}}{T}$

The wavelengths are inversely proportional to the temperature.

According to stellar spectral types

The standard classes

Spectral classes -Temperature - color of stars

M < 3500 K - Red

K - 3500 - 5000 K - Yellow orange

G - 5000 - 6000 K - Yellow

F - 6000 - 7500 K - Yellow white

A - 7500 - 10000 K - white

B - 10000 - 30000 K - Blue white

O - 30000 - 60000 K - Blue

Hence, The color of a star be with a surface temperature of 5000 6000 K is Yellow.

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3 years ago

An interference pattern is produced by light with a wavelength 550 nm from a distant source incident on two identical parallel s

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Answer:

$\theta = 0.0022 rad$

$I = 0.000304 I_o$

Explanation:

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$dsin \theta = m \lambda$

Where m is the order which is given from the question as m = 2

=> $\theta = sin ^{-1} [\frac{m \lambda}{d} ]$

substituting values

$\theta = 0.0022 rad$

Now on the second question

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$d = 0.300 \ mm = 3.0 *10^{-4} \ m$

The intensity at the the angular position in part "a" is mathematically evaluated as

$I = I_o [\frac{sin \beta}{\beta} ]^2$

Where $\beta$ is mathematically evaluated as

$\beta = \frac{\pi * d * sin(\theta )}{\lambda }$

substituting values

$\beta = \frac{3.142 * 3*10^{-4} * sin(0.0022 )}{550 *10^{-9} }$

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3 years ago