Scientists collected evidence to form a valid theory about the formation and early development of the solar system include:
- Stars forming the depths of giant clouds of gas and dust.
- Young stars with disks of debris around them.
<h3>
What is Solar system?</h3>
This is referred to the gravitationally bound system of the Sun and the objects that orbit it.
It also comprises of the planets and their moons and objects such as asteroids and the evidence which shows that the formation of the solar system are the gas and dust which form the stars and debris found around them.
This therefore makes it the evidence collected in the formation of the solar system mentioned the most appropriate choice.
Read more about Solar system here brainly.com/question/1286910
#SPJ1
You can develop acute radiation syndrome or skin cancer.
<span>HCl<span>(aq)</span>+NaOH<span>(aq)</span>→NaCl<span>(aq)</span>+<span>H2</span>O<span>(l)</span></span>
As you can see here, one mole of acid neutralizes one mole of base.
We use the concentration equation, which states that,
<span>c=<span>nv</span></span>
<span>
<span>
<span>
n is the number of moles
</span>
<span>
v is the volume of solution
</span>
</span>
</span>
Rearranging for moles, we get,
<span>n=c⋅v</span>
So, we have:
<span><span>n<span>NaOH</span></span>=0.1 M⋅0.05 L</span>
<span>=0.005 mol</span>
Since one mole of acid neutralizes one mole of base, then we must have: <span><span>n<span>HCl</span></span>=<span>n<span>NaOH</span></span></span>.
And so,
<span><span>c<span>HCl</span></span>=<span><span>n<span>HCl</span></span><span>v<span>HCl</span></span></span></span>
<span>=<span><span>0.005 mol</span><span>0.03 L</span></span></span>
<span>≈0.17 <span>M</span></span>
Answer:
The rate of the reaction increased by a factor of 1012.32
Explanation:
Applying Arrhenius equation
ln(k₂/k₁) = Ea/R(1/T₁ - 1/T₂)
where;
k₂/k₁ is the ratio of the rates which is the factor
Ea is the activation energy = 274 kJ/mol.
T₁ is the initial temperature = 231⁰C = 504 k
T₂ is the final temperature = 293⁰C = 566 k
R is gas constant = 8.314 J/Kmol
Substituting this values into the equation above;
ln(k₂/k₁) = 274000/8.314(1/504 - 1/566)
ln(k₂/k₁) = 32956.4589 (0.00198-0.00177)
ln(k₂/k₁) = 6.92
k₂/k₁ = exp(6.92)
k₂/k₁ = 1012.32
The rate of the reaction increased by 1012.32
