What is the volume (in liters) of a 5.52 gram sample of O2 at STP?
1 answer:
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Answer:
(a) 1 atm, 8.72 L and 298 K respectively.
(b) 1 atm, 16.72 L and 573.35 K respectively.
(c)
Explanation:
Hello,
(a) In this case, considering that neon could be considered as an ideal gas, we can compute its volume as follows:
Thus, initial conditions of pressure volume and temperature are 1 atm, 8.72 L and 298 K respectively.
(b) Since the process was carried out at constant pressure, the work is defined as:
Thus, the final volume is:
And the final temperature is computed by considering the pressure-constant specific heat of neon (1.03 J/g*K) and the added heat:
Therefore, final volume is 16.72 L, final pressure is also 1 atm and final temperature is 573.35 K for this expansion process.
(c) Finally, the change in the internal energy is computed via the first law of thermodynamics:
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Answer:- Volume decreases by a factor of 1.15.
Solution:- At constant pressure, volume of the gas is directly proportional to the the kelvin temperature.
The equation is written as:
where, is the volume at initial temperature
and
is the volume at final temperature
.
Temperature must be in kelvins. So, let's convert both the temperatures to kelvin.
To convert degree C to kelvin we add 273.
So, = 100 + 273 = 373 K
= 50 + 273 = 323 K
The equation could also be written as:-
= 1.15
From here we could say that the volume decreases by a factor of 1.15.
For example if the initial volume is 1 L then final volume
will be
that is 0.87 L.