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AfilCa [17]
2 years ago
6

What is the volume (in liters) of a 5.52 gram sample of O2 at STP?

Chemistry
1 answer:
OverLord2011 [107]2 years ago
4 0

Answer:

1

Recall that at STP, 1 mole of any ideal gas occupies 22.4 liters. Volume O2 gas = 0.0510 moles O2 x 22.4 L/mole = 1.14 liters (3 sig.

Explanation:

hope this helps

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In Valence Shell Electron Pair Repulsion Theory (VSEPR),
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Answer: look at the close because that is the answer

Explanation:

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In one step in the synthesis of the insecticide Sevin, naphthol reacts with phosgene as shown.
Serhud [2]

Answer:

Explanation:

Chemical equation:

C₁₀H₈O + COCl₂  → C₁₁H₇O₂Cl + HCl

A. How many kilograms of C₁₁H₇O₂Cl form from 2.5×10*2 kg of naphthol?

Given data:

Mass of naphthol = 2.5 ×10² kg ( 250×1000 = 250000 g)

Mass of C₁₁H₇O₂Cl = ?

Solution:

Number of moles of naphthol = mass/ molar mass

Number of moles of naphthol = 250000 g/ 144.17 g/mol

Number of moles of naphthol = 1734.1 mol

Now we will compare the moles of naphthol with C₁₁H₇O₂Cl.

                     C₁₀H₈O       :         C₁₁H₇O₂Cl

                        1               :                1

                       1734.1         :             1734.1

Mass of C₁₁H₇O₂Cl:

Mass = number of moles × molar mass

Mass = 1734.1 mol × 206.5 g/mol

Mass = 358091.65 g

Gram to kilogram:

1 kg×358091.65 g/ 1000 g  = 358.1 kg

B. If 100. g of naphthol and 100. g of phosgene react, what is the theoretical yield of C11H7O2Cl?

Given data:

Mass of naphthol = 100 g

Mass of COCl₂ = 100 g

Theoretical yield of C₁₁H₇O₂Cl = ?

Solution:

Number of moles of naphthol:

Number of moles of naphthol = mass/ molar mass

Number of moles of naphthol = 100 g/ 144.17 g/mol

Number of moles of naphthol = 0.694 mol

Number of moles of phosgene:

Number of moles  = mass/ molar mass

Number of moles =  100 g/ 99 g/mol

Number of moles = 1.0 mol

Now we will compare the moles of naphthol and phosgene with C₁₁H₇O₂Cl.

                     C₁₀H₈O        :         C₁₁H₇O₂Cl

                        1                :                1

                       0.694        :              0.694

                    COCl₂          :             C₁₁H₇O₂Cl

                        1                :                1

                       1.0              :              1.0

The number of moles of C₁₁H₇O₂Cl produced by C₁₀H₈O are less so it will limiting reactant and limit the yield of  C₁₁H₇O₂Cl.

Mass of C₁₁H₇O₂Cl:

Mass = number of moles × molar mass

Mass =  0.694 mol × 206.5 g/mol

Mass = 143.3 g

Theoretical yield  =  143.3 g

C. If the actual yield of C11H7O2Cl in part b is 118 g, what is the percent yield?

Given data:

Actual yield of C₁₁H₇O₂Cl = 118 g

Theoretical yield = 143.3 g

Percent yield = ?

Solution:

Formula :

Percent yield = actual yield / theoretical yield × 100

Now we will put the values in formula.

Percent yield = 118 g/ 143.3 g × 100

Percent yield = 0.82 × 100

Percent yield = 82%

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You conduct an experiment in which you measure the temperature (T) and volume (V) of a mysterious sphere of gas at several diffe
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Volume of the gas is 525 L.

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It is given that the volume of the gas divided by the temperature is 1.75.

V/T = 1.75

As per the Charles law, volume is proportional to the temperature.

V ∝ T

V/T = constant

Now we have to find V, and T is given as 300 K.

So plugin the values as,

V/300 = 1.75

Rearranging the equation to get V as,

V = 1.75×300

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3 0
3 years ago
What type of atom is hydrogen with an atomic mass of 1 and 2 electrons
Charra [1.4K]

Answer:

This would be the hydride ion where H gains an electron from a metal such as  Na

Explanation:

7 0
3 years ago
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