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natulia [17]
3 years ago
10

Carbon can be used to displace some metals from their ores. Explain the process by which iron is displaced from its ore by carbo

n in a blast furnace. Include the reaction equation. *
Chemistry
1 answer:
RideAnS [48]3 years ago
7 0

<em>Iron is extracted from iron ore in a huge container called a blast furnace. Iron ores such as hematite contain iron(III) oxide, Fe2O3. The oxygen must be removed from the iron(III) oxide in order to leave the iron behind. Reactions in which oxygen is removed are called reduction reactions.</em>

<em>Carbon is more reactive than iron, so it can displace iron from iron(III) oxide. Here are the equations for the reaction.</em>

Step 1 – Hot air (oxygen) reacts with the coke (carbon) to produce carbon dioxide and heat energy to heat up the furnace.

C(s) + O2(g) → CO2(g)

Step 2 – More coke is added to the furnace and reduces the carbon dioxide into carbon monoxide, a good reducing agent.

<em>CO2(g) + C(s) → 2CO(g)</em>

Step 3 – iron(III) oxide is reduced.

iron(III) oxide + carbon → iron + carbon dioxide

<em>2Fe2O3(s) + 3C(s) → 4Fe(l) + 3CO2(g)</em>

In this reaction, the iron(III) oxide is reduced to iron, and the carbon is oxidized to carbon dioxide.

In the blast furnace, it is so hot that carbon monoxide can be used, in place of carbon, to reduce the iron(III) oxide:

<em>iron(III) oxide + carbon monoxide → iron + carbon dioxide</em>

<em>Fe2O3(s) + 3CO(g) → 2Fe(l) + 3CO2(g)</em>

<em />

<em>More than you asked </em>

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3 years ago
Aqueous solutions of aluminum sulfate and barium chloride are mixed, resulting in the precipitate formation of barium sulfate wi
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Answer:

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Explanation:

The question wants you to use the lowest possible coefficients to balance the equation.

According to the question the reaction is as follows ;

Generally, writing the chemical formula requires one to exchange the charge between the cations and anions involved. Example aluminum sulfate has Al3+ and (SO4)2- . cross multiply the charges to get Al2(SO4)3

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Al2(SO4)3(aq) + BaCl2(aq) → BaSO4(s) + AlCl3(aq)

To balance a chemical equation one have to make sure the number of atom of element on the reactant side(left) is equal to the number of atom of elements on the product side(right).

Now, the equation can be be balance with the lowest coefficient as follows;

Al2(SO4)3(aq) + 3BaCl2(aq) → 3BaSO4(s) + 2AlCl3(aq)

The bold numbers is the coefficient use to balance the equation.

The number of atom on the reactant side is equal to the product side. Using aluminium atom as a case study the number of aluminium atom on the reactant side is 2 and the on the product  side it is also  2.

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Explanation:

4 0
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