All categories

4 years ago

What is the average velocity between 3.00 and 6.00 seconds?

Chemistry

2 answers:

diamong [38]4 years ago

8 0

1)
average velocity:
(3,9)
(6,36)
average velocity=(36-9)m/(6-3) s=27m/3s=9 m/s

Answer: 9 m/s, east.

2)
(12, 144)
(15,225)
average velocity=(225-144)m/(15-12)s=81 m/3s=27 m/s

Answer: 27 m/s,east.

ehidna [41]4 years ago

8 0

Answer :

(1) The correct option is, 9.00 m/s, east

(2) The correct option is, 27.00 m/s, east

Explanation :

Average velocity : It is defined as the change in the displacement with respect to the change in time.

Formula used :

$V_{average}=\frac{\Delta d}{\Delta t}=\frac{d_{final}-d_{initial}}{t_{final}-t_{initial}}$

where,

d = displacement

t = time

(1) Now we have to calculate the average velocity between 3.00 and 6.00 seconds.

$V_{average}=\frac{36m-9m}{6s-3s}=9m/s$

The average velocity between 3.00 and 6.00 seconds is, 9 m/s, east

(2) Now we have to calculate the average velocity between 12.00 and 15.00 seconds.

$V_{average}=\frac{225m-144m}{15s-12s}=27m/s$

The average velocity between 12.00 and 15.00 seconds is, 27 m/s, east

Therefore, (1) The correct option is, 9.00 m/s, east

(2) The correct option is, 27.00 m/s, east

You might be interested in

An outdoor grill has a propane (C3H8) tank that holds 4.8 L of gas at a pressure of 5.5 atm. If all of the gas is transferred in

shtirl [24]

Answer: 0.176 atm

Explanation: Solution attached:

Use Boyle's Law to find the new pressure of the gas.

P1V1 = P2V2

Derive for P2

P2 = P1V1 / V2

= 5.5 atm ( 4.8 L ) / 150 L

= 0.176 atm

4 0

3 years ago

All the following steps need to be followed when naming alkanes, except

goldfiish [28.3K]

Begin numbering at the end closest to the first branch, not the farthest.

6 0

4 years ago

Read 2 more answers

All the following ions have the same charge except Group of answer choices oxide. monohydrogen phosphate. peroxide. permanganate

Triss [41]

All the given species have the same charge except peroxide.

<h3>Charges on ions</h3>

The charge on monohydrogen phosphate is negative because of its formula, $[HPO4]^{2-}$ .

The charge on permanganate is negative. The formula is $MnO^-$

The charge of oxide ( $O^{2-}$ ) is negative.

The charge on peroxide is ( R−O−O−R) is neutral.

The charge on oxalate, $C2O4^{2-}$ , is negative.

Thus, only peroxide is unique.

More on charges on ions can be found here: brainly.com/question/11938054

#SPJ3

4 0

2 years ago

Benzene is a starting material in the synthesis of nylon fibers and polystyrene (styrofoam). Its specific heat capacity is 1.74

katovenus [111]

Answer:

Explanation:

The amount of energy released or absorbed is equal the product of the mass, the specific heat capacity and the temperature change. The temperature change being the difference between the final and initial temperature.

Q = mc∆T

Q = heat energy (Joules, J) m = mass of a substance (kg) c = specific heat (units J/g∙K)

∆ is a symbol meaning "the change in" ∆T = change in temperature (Kelvins, K)

From the data provided in the question, we can deduce that:

Q = 16.7KJ = 16,700J

m = 225g

c = 1.74J/g.k

For the temperature, let the final temperature be f. This means our ∆T = f - 20

16,700 = 225 * 1.74 * (f - 20)

16700 = 391.5 (f - 20)

f - 20 = 16700/391.5

f - 20 = 42.7

f = 20 + 42.7 = 62.7

Hence the final temperature is 62.7 degrees Celsius

6 0

4 years ago

The density of ethanol, C 2H 5OH, is 0.789 g/mL. How many milliliters of ethanol are needed to produce 25.0 g of CO 2 according

gogolik [260]

Answer:

11.1mL

Explanation:

The reaction expression is given as:

C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O

Given parameters:

density of ethanol = 0.789g/mL

mass of CO₂ = 25g

Unknown:

Volume of ethanol = ?

Solution:

First find the number of moles of the CO₂ from the given mass;

Number of moles = $\frac{mass}{molar mass}$

Molar mass of CO₂ = 12 + 2(16) = 44g/mol

Number of moles = $\frac{25}{44}$ = 0.57mol

Then;

Find the number of moles of ethanol used;

3 moles of CO₂ is produced from 1 mole of ethanol;

0.57mole of CO₂ will be produced from $\frac{0.57}{3}$ = 0.19mole of ethanol

Now;

Find the mass of the ethanol from the given mole;

Mass of ethanol = number of moles x molar mass

Molar mass of ethanol = 2(12) + 5(1) + 16 + 1 = 46g/mol

Mass of ethanol = 0.19 x 46 = 8.74g

Then;

Density is the mass per unit volume of a substance;

Density = $\frac{mass}{volume}$

Volume = $\frac{mass}{density}$

Volume = $\frac{8.74}{0.789}$ = 11.1mL

5 0

3 years ago