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svetlana [45]
3 years ago
7

Which of the following would

Chemistry
1 answer:
nadezda [96]3 years ago
4 0

Answer: A forest

Explanation:

Moss are more likely to be found in moist shady locations. They are best known for those species that carpet woodland and forest floors.

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4. A 134.0 g sample of an unknown metal is heated to 91.0°C and then placed in 125 g of water at 25.0°C. The final temperature o
Gnom [1K]

Answer:

Oi ima french Not really

Explanation:

7-7 = 0 andbecause it is so ima done

7 0
3 years ago
A possible mechanism for the overall reaction Br2 (g) + 2NO (g) → 2NOBr (g) is NO (g) + Br2 (g) rightwards arrow with k space 1
omeli [17]

Answer : The rate law for formation of NOBr based on this mechanism is, \frac{k_1\times k_2}{k_1^-}[Br_2][NO]^2

Explanation :

The overall reaction is:

Br_2(g)+2NO(g)\rightleftharpoons 2NOBr(g)

Rate law = k[Br_2][NO]^2

The first step of the overall reaction is:

NO(g)+Br_2(g)\overset{k_1}{\rightarrow} NOBr_2(g)

NO(g)+Br_2(g)\overset{k_1^-}{\leftarrow} NOBr_2(g)

Rate law 1 = k_1[Br_2][NO]

Rate law 2 = k_1^-[NOBr_2]

The second step of the overall reaction is:

NOBr_2(g)+NO(g)\overset{k_2}{\rightarrow} 2NOBr

Rate law 3 = k_2[NOBr_2][NO]

Now rate law of overall reaction can be obtained as follows.

We are multiplying rate law 1 and rate law 3 and dividing by rate law 2, we get:

Rate law = \frac{[k_1[Br_2][NO]]\times [k_2[NOBr_2][NO]]}{[k_1^-[NOBr_2]]}

Rate law = \frac{k_1\times k_2}{k_1^-}[Br_2][NO]^2

Rate law = k[Br_2][NO]^2

The rate law for formation of NOBr based on this mechanism is, \frac{k_1\times k_2}{k_1^-}[Br_2][NO]^2

4 0
3 years ago
What is molar mass......?
Savatey [412]

In chemistry, the molar mass M is a physical property defined as the mass of a given substance (chemical element or chemical compound) divided by its amount of substance. The base SI unit for molar mass is kg/mol. However, for historical reasons, molar masses are almost always expressed in g/mol.

Hope this helped!

Good luck :p

~Emmy <3

4 0
3 years ago
Read 2 more answers
A 4.24 kg marble slab has a volume of 1564 cm³ what is its density in grams per centimeters cubed
tangare [24]

Answer:2.71g/cm3

Explanation:

7 0
4 years ago
a chunk of lead at 91.6 C was added to 200.0g of water at 15.5 C. The specific heat of lead is 0.129J/g C. When the temperature
worty [1.4K]
Let's apply the conservation of energy through the equation below:

Q for lead + Q for water = 0
So,
Q for lead = -Q for water
where
Q = mass*specific heat*(T₂ - T₁)
The specific heat of liquid water is 4.187 J/g·°C

Substituting the values:
(m)(0.129 J/g·°C)(17.9 - 91.6°C) = -(200 g)(4.187 J/g·°C)(17.9 - 15.5°C)
Solving for m,
m = <em>211.39 grams of lead</em>

4 0
3 years ago
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