What Can you be more clear --Molecules change it from being less dense
Answer:
0.607mol
Explanation:
n(AR) = mass / molar máss
= 24.3 /40
=0.607
The answer is 2 more oxygen is needed
2CH4 + 2NH3 + 3O2 ---> 2HCN + 6H2O
10g CH4 x 1molCH4/16.042gCH4 x 2mol HCN/2molCH4 = 0.6mol HCN
12g NH3 x 1molNH3/17.034gNH3 x 2molHCN/2molNH3 = 0.7mol HCN
Methane is the limiting reactant
Use the moles of Hydrogen Cyanide that you would get when used the limiting reactant, Methane
0.6molHCN x 27.028gHCN/1molHCN = 16.2grams --> 16 grams Methane
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