What flows in electricity?<br> A. Electrons<br> B. Protons<br> C. Neutrons

Assume you are in the car and the car is moving at a certain speed to

Setler79 [48]

You are at rest with respect to the car.
You are in motion with respect to the School.

6 0

3 years ago

A wildlife researcher is tracking a flock of geese. The geese fly 4.0 km due west, then turn toward the north by 40º and fly ano

Kobotan [32]

Wildlife researcher starts from a and then reaches b, he turns towards north 40 degree to move towards c.

Total displacement is ac

Total horizontal displacement = 4+4 cos40 =7.06 km

Total vertical displacement = 4 sin40 =2.57 km

Total displacement $= \sqrt{7.06^2+2.57^2}$ = 7.51 km

7 0

3 years ago

Ask Your Teacher The height h in feet reached by a dolphin t seconds after breaking the surface of the water is given by h = −16

kirza4 [7]

Answer:

1 second

Explanation:

h = −16t² + 32t

When, h = 16

16 = −16t² + 32t

Divide each of the numbers by 16

1 = -1t² + 2t

Rearrange the equation

1t²-2t+1 = 0

Solving by the quadratic formula, we get

$t=\frac{-(-2)\pm \sqrt{(-2)^2-4\times 1\times 1}}{2\times 1}\\\Rightarrow t=\frac{2\pm 0}{2}\\\Rightarrow t=1\ s$

So, time taken by the dolphin to jump out of the water and touch the trainer's hand is 1 second.

3 0

3 years ago

I’m so confused. please help. i don’t know what i’m suppose to do

aniked [119]

Answer:

Maybe put them in order ????

Explanation:

4 0

3 years ago

Um corpo de massa 50g recebe 300 calorias e sua temperatura sobe de -10°C até 20°C. Determine a capacidade térmica do corpo e o

kykrilka [37]

The specific heat capacity of the substance is $0.963 J/g^{\circ}C$

Explanation:

When an object of mass m is supplied with a certain amount of energy Q, its temperature increases according to the equation:

$Q=mC_s \Delta T$

where

m is the mass of the object

$C_s$ is its specific heat capacity

$\Delta T$ is the increase in temperature of the object

In this problem, we have

$Q=300 cal \cdot 4.814 = 1444.2 J$

m = 50 g

$\Delta T = 20C-(-10C)=30^{\circ}C$

Therefore, we can solve for $C_s$ to find its specific heat capacity:

$C_s = \frac{Q}{m\Delta T}=\frac{1444.2}{(50)(30)}=0.963 J/gC$

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

7 0

3 years ago

What flows in electricity? A. Electrons B. Protons C. Neutrons