A 4.2 m board with a mass of 19 kg is pivoted at its center of gravity. A helium balloon attached 0.24 m from the left end of th
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To solve this problem it is necessary to apply the concepts related to frequency and vibration of strings. Mathematically the frequency can be expressed as
Then the relation between two different frequencies with same wavelength would be
The beat frequency heard when the two strings are sounded simultaneously is
We have the velocity of the transverse waves in stretched string as
And,
Therefore the relation between the two is,
Finally substituting this value at the frequency beat equation we have
Therefore the beats per second are 11.92Hz