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yaroslaw [1]
3 years ago
6

A 4.2 m board with a mass of 19 kg is pivoted at its center of gravity. A helium balloon attached 0.24 m from the left end of th

e board produces an upward force of 7.1 N. A 3.5 kg book is placed 0.74 m from the left end of the board, and another book of 1.7 kg is placed 0.77 m from the right end of the board. Find the torque on the board and the direction of rotation. (Hint: add the torques.)
Physics
1 answer:
storchak [24]3 years ago
6 0

Answer:

The torque on the board = 11.8 Nm in the anti-clockwise direction

Explanation:

Please find attached the explanation to the answer given.

Download docx
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In the first stage of a two-stage Carnot engine, energy is absorbed as heat Q1 at temperature T1 = 500 K, work W1 is done, and e
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Answer:

Efficiency = 52%

Explanation:

Given:

First stage

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Heat released, Q₂ at temperature T₂ = 430 K

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Second stage

Heat released, Q₂ at temperature T₂ = 430 K

Heat released, Q₃ at temperature T₃ = 240 K

and the work done is W₂

Total work done, W = W₁ + W₂

Now,

The efficiency is given as:

\eta=\frac{\textup{Total\ work\ done}}{\textup{Energy\ provided}}

or

Work done = change in heat

thus,

W₁ = Q₁ - Q₂

W₂ = Q₂ - Q₃

Thus,

\eta=\frac{(Q_1-Q_2)\ +\ (Q_2-Q_3)}{Q_1}}

or

\eta=1-\frac{(Q_1-Q_3)}{Q_1}}

or

\eta=1-\frac{(Q_3)}{Q_1}}

also,

\frac{Q_1}{T_1}=\frac{Q_2}{T_2}=\frac{Q_3}{T_3}

or

\frac{T_3}{T_1}=\frac{Q_3}{Q_1}

thus,

\eta=1-\frac{(T_3)}{T_1}}

thus,

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or

\eta=0.52

or

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Answer:

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